Answer:
0.000003782 m
0.000001891 m
0.000001197125 m
Explanation:
= Wavelength = 248 nm
D = Diameter of beam = 1 cm
f = Focal length = 0.625 cm
The angle is given by
The width is given by
The required width is 0.000003782 m
Minimum resolvable line separation is given by
The minimum resolvable line separation between adjacent lines is 0.000001891 m
when 
The new minimum resolvable line separation between adjacent lines is
<span>High SchoolPhysics5+3 pts</span><span>Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each term with its definition. Tiles conductor radiation insulator convection conduction Pairs heat transfer involving direct contact of particles arrowBoth heat transfer in fluids arrowBoth heat transfer that doesn’t need a medium arrowBoth substance that doesn’t allow heat through arrowBoth substance that allows heat through arrowBoth
These are the answers:
</span>Conductor - <span>substance that allows heat through
</span>Radiation - <span> heat transfer that doesn’t need a medium
</span>Insulator - <span>substance that doesn’t allow heat through
</span>Convection - <span>heat transfer in fluids
Conduction - </span>heat transfer involving direct contact of particles
Impulse = Integral of F(t) dt from 0.012s to 0.062 s
Given that you do not know the function F(t) you have to make an approximation.
The integral is the area under the curve.
The problem suggest you to approximate the area to a triangle.
In this triangle the base is the time: 0.062 s - 0.012 s = 0.050 s
The height is the peak force: 35 N.
Then, the area is [1/2] (0.05s) (35N) = 0.875 N*s
Answer> 0.875 N*s
Answer:
The gravitational force exerted on the object is 75 N (answer D)
Explanation:
Hi there!
The gravitational force is calculated as follows:
F = m · g
Where:
F = force of gravity.
m = mass of the object.
g = acceleration due to gravity (unknown).
For a falling object moving in a straight line, its height at a given time can be calculated using the following equation:
y = y0 + v0 · t + 1/2 · a · t²
Where:
y = position at time t.
y0 = initial position.
v0 = initial velocity.
t = time.
g = acceleration due to gravity.
Let´s place the origin of the frame of reference at the point where the object is released so that y0 = 0. Let´s also consider the downward direction as negative.
Then, after 2 seconds, the height of the object will be -30 m:
y = y0 + v0 · t + 1/2 · g · t²
-30 m = 0 m + 0 m/s · 2 s + 1/2 · g · (2 s)²
-30 m = 1/2 · g · 4 s²
-30 m = 2 s ² · g
-30 m/2 s² = g
g = -15 m/s²
Then, the magnitude of the gravitational force will be:
F = m · g
F = 5 kg · 15 m/s²
F = 75 N
The gravitational force exerted on the object is 75 N (answer D)
Have a nice day!
The one that is loaded worst. The overall weight is not important; tongue weight is a matter of loading. Our 12,000 lb snow cat trailer, which has stops to position the cat properly, has under 100 lbs tongue weight. Excessive tongue weight is a Bad Thing because it reduces weight on the towing vehicle's front wheels, leading to instability.
