A source charge of 3 µC generates an electric field of 2.86 × 105 N/C at the location of a test charge. Using k = 8.99 × 109N.m^
2 answers:
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Answer:
Wavelength of incident light,
Given:
Distance between slit and screen, x = 5.00 m
slit width, d = 0.180 mm
width of the fringe,
Solution:
To calculate the wavelength of the incident light, :
Answer:
At 30 degrees, height = 14.39 m and distance = 49.83 m
At 45 degrees, height = 28.77 m and distance = 57.54 m
At 60 degrees, height = 43.16 m and distance = 49.83 m
Explanation:
Let ∝ be the angle with respect to the horizontal that the baseball is hit with.
The horizontal component of the velocity is vcos(∝) and the vertical component of the velocity is vsin(∝).
Ignore air resistant, only gravitational acceleration g = -9.81 m/s2 affect the ball vertically. We can use the following equation to calculate the time it takes to reach maximum height (at 0 speed)
So the vertical distance it travels within time t is
Similarly the horizontal distance it travels within time t is:
We can pre-calcualte the quantity
So
From here we can plug-in the angles values of 30, 45 and 60 degrees
At 30 degrees, height = 14.39 m and distance = 49.83 m
At 45 degrees, height = 28.77 m and distance = 57.54 m
At 60 degrees, height = 43.16 m and distance = 49.83 m