Answer:
Explanation:
If I assume that the wind did not cause the plane to chage its velocity.
The plane will have a velocity of vp = (0*i + 100*j) km/h relative to ground
The cart has a velocity of vc = (0*i - 20*j) km/h relative to the plane
vc' = vc + vp
vc' = (0*i + 100*j) + (0*i - 20*j) = (0*i + 80*j) km/h relative to the ground.
If I assume that the wind move the plane:
The plane will have a velocity of vp = (-40*i + 100*j) km/h relative to ground
The cart has a velocity of vc = (0*i - 20*j) km/h relative to the plane
vc' = vc + vp
vc' = (-40*i + 100*j) + (0*i - 20*j) = (-40*i + 80*j) km/h relative to the ground.
In reality the wind would move the plane a little, not to the full speed of the wind, somewhere between these two values, but without more data it cannot be calculated.
As we know that

here we know that


now from above equation we have


so image will form on left side of lens at a distance of 15 cm
This image will be magnified and virtual image
Ray diagram is attached below here
Use this formula
Vf = sqrt(2gh)
Answer:
α = (ω²)/8π
Explanation:
The angular acceleration(α) of the carousel can be determined by using rotational
kinematics:
ω² =ωo² + 2αθ
Let's make α the subject of this equation ;
ω² - ωo² = 2αθ
α = (ω² −ωo²)/2θ
Now, from the question, since initially at rest, thus, ωo = 0
Also,since 2 revolutions, thus, θ = 2 x 2π = 4π since one revolution is 2π
Plugging in the relevant values to get ;
α = (ω²)/2(4π)
α = (ω²)/8π
the first one is medium, the second one is type, and the third one is temperature
. if i gave the correct answer, please give best answer x