Missing detail in the text: total voltage of the circuit
Missing figure: https://www.physicsforums.com/attachments/prob-24-68-jpg.190851/
Solution:
1) The energy stored in a circuit of capacitors is given by
where
is the equivalent capacitance of the circuit. We can find the value for
by using
and the energy of the system,
2) Then, let's calculate the equivalente capacitance of C1 and C2. The two capacitors are in series, so their equivalente capacitance is given by
from which we find
3) Then let's find
, the equivalent capacitance of
and C3.
is in series with C4, therefore we can write
Since we already know
and
, we find
4) Finally, we can find
, because it is in parallel with
, and the equivalent capacitance of the two must be equal to
:
So, using
and
, we find
Answer:
Tension T in each rope will be 254.56 N.
Explanation:
From the picture attached,
Weight suspended by the two ropes will be supported by the vertical components of the tension in the ropes.
Vertical components of both the ropes = Tsin(45)° + Tsin(45)°
= 2Tsin(45)°
= 
= 
Since, 
T = 
T = 254.56 N
Therefore, tension T in each rope will be 254.56 N.
Answer:
A) If one travels around a closed path adding the voltages for which one enters the negative reference and subtracting the voltages for which one enters the positive reference, the total is zero.
Explanation:
Kirchhoff's voltage law deals with the conservation of energy when the current flows in a closed-loop path.
It states that the algebraic sum of the voltages around any closed loop in a circuit is always zero.
In other words, the algebraic sum of all the potential differences through a loop must be equal to zero.
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
Good morning.
Lets make the movement function for the dog and cat.
The cat has a start position of
1.5 m(the middle of the room), with an initial speed of
0 and acceleration of
0.85 m/s².
The dog has a start position of
0, an initial speed of
1.5 m/s and acceleration of
-0.1 m/s².
<u>Cat:</u>
<u>Dog:</u>
Let's see if the dog reach the cat. Physically, it means
Now we solve for <em>t</em>:
We have a negative Delta.
Therefore, there is no instant t when the dog reaches the cat.
