Question

The magnitude of the force associated with the gravitational field is constant and has a value F. A particle is launched from point B with an initial velocity and reaches point A having gained U0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12F. A particle is again launched from point B. How much kinetic energy will the particle gain as it moves from point B to point A

Answer 1

Answer:

Energy gained by the second particle = 12Uo

Explanation:

Given Data;

Resistant force = 12F

Initial kinetic energy = Uo

Calculating the kinetic energy gained, we have;

u = f *r

where f= resistant force = 20F

r = initial kinetic energy = Uo

Therefore,

U = 12 * uo

  = 12 Uo

Therefore, energy gained by the second particle = 12Uo