Question

1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy. Determine the binding energy per nucleon of an Mg-24 nucleus. The Mg-24 nucleus has a mass of 23.985045. A proton has a mass of 1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy.
a.8.01 MeV
b.192 MeV
c.0.113 MeV
d.4.41 MeV
e.0.3050 MeV

Answer 1

Answer:

192.16MeV

Explanation:

Mass of neutron (Mn) = 1.008665 amu

Mass of proton (Mp) = 1.00728 amu

Mass of nucleus (Mg-24) = 23.985045 amu

1 amu = 931.5MeV

Binding energy of the nucleus is the work or energy needed just to take all the entire nucleons apart so that they are completely separated.

Mass defect = (mass of proton + mass of neutron) - mass of nucleus.

Mass defect = [12(1.00728) + 12(1.008665)] - 23.985045

Mass defect = [(12.08736 + 12.10398)] - 23.985045

Mass defect = 24.19134 - 23.985045

Mass defect = 0.206295amu

Binding energy = mass defect * 931.5 MeV

Binding energy = 0.206295 * 931.5

Binding energy = 192.16MeV