Answer:
h = 20.36[m]
Explanation:
To solve this problem we must calculate the perimeter (length of a circumference) of the circumference, which is denoted by the following equation:
L = 2*π*r
where:
r = radius = 0.9[m]
π = 3.1416
L = 2*(3.1416)*(0.9)
L = 5.654[m]
Now we know that the pulley or circumference had to rotate 3.6 times to get the water out of the well. In this way the depth of the well can be calculated by means of the following equation:
h = 3.6*L
h = 3.6*5.654
h = 20.36[m]
Answer:
303 Ω
Explanation:
Given
Represent the resistors with R1, R2 and RT
R1 = 633
RT = 205
Required
Determine R2
Since it's a parallel connection, it can be solved using.
1/Rt = 1/R1 + 1/R2
Substitute values for R1 and RT
1/205 = 1/633 + 1/R2
Collect Like Terms
1/R2 = 1/205 - 1/633
Take LCM
1/R2 = (633 - 205)/(205 * 633)
1/R2 = 428/129765
Take reciprocal of both sides
R2 = 129765/428
R2 = 303 --- approximated
Assuming that this gas is in ideal state, we can use the relation that for every 1 mol of an ideal gas it would have a volume of 22.4 L. But before using this, relation we need to convert the number of grams of H2 into moles by using the molar mass of 2.02 g/mol.
moles H2 = 0.00922 g ( 1 mol / 2.02 g ) = 0.005 mol H2
Volume H2 at STP = 0.005 mol H2 ( 22.4 L / 1 mol ) = 0.102 L of H2
Answer:
a = 18.28 ft/s²
Explanation:
given,
time of force application, t= 10 s
Work = 10 Btu
mass of the object = 15 lb
acceleration, a = ? ft/s²
1 btu = 778.15 ft.lbf
10 btu = 7781.5 ft.lbf
m = 0.466 slug
now,
work done is equal to change in kinetic energy
now, acceleration of object
a = 18.28 ft/s²
constant acceleration of the object is equal to 18.28 ft/s²
Answer:
Answer:
1.1 x 10^9 ohm metre
Explanation:
diameter = 1.5 mm
length, l = 5 cm
Potential difference, V = 9 V
current, i = 230 micro Ampere = 230 x 10^-6 A
radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m
Let the resistivity is ρ.
Area of crossection
A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2
Use Ohm's law to find the value of resistance
V = i x R
9 = 230 x 10^-6 x R
R = 39130.4 ohm
Use the formula for the resistance
ρ = 1.1 x 10^9 ohm metre
Explanation:
