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Svetllana [295]

2 years ago

15

a pulley of radius 0.9m is used to lift a bucket from the well. if it took 3.6 rotations for the pulley to take water out of the

well,how deep is water in the well?

1 answer:

Alex777 [14]2 years ago

6 0

Answer:

h = 20.36[m]

Explanation:

To solve this problem we must calculate the perimeter (length of a circumference) of the circumference, which is denoted by the following equation:

L = 2*π*r

where:

r = radius = 0.9[m]

π = 3.1416

L = 2*(3.1416)*(0.9)

L = 5.654[m]

Now we know that the pulley or circumference had to rotate 3.6 times to get the water out of the well. In this way the depth of the well can be calculated by means of the following equation:

h = 3.6*L

h = 3.6*5.654

h = 20.36[m]

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Answer:

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Explanation:

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2 years ago

A pipe contains water at 500,000 Pa above atmospheric pressure. If you patch a 4.00 mm diameter hole in the pipe with a piece of

IRISSAK [1]

Answer: 6.284N

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Pressure = Force/Area

Pressure = 500,000Pa

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If d = 4mm = 0.004m

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What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

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Answer:

$4.3\cdot 10^{-12} J$

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The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

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So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

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Answer:

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