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2 years ago

Explain how energy is conserved when nuclear fission or fusion occurs

Physics

2 answers:

andriy [413]2 years ago

6 0

Answer:

The energy is conserved in the nuclear fission when the nuclear reactor mass releases the kinetic energy in the reaction and then source is known as the nuclear binding energy.

By using the Einstein mass energy equation that is E = m×c², we can easily determine the actual amount of the released energy. The nuclear fission is the process of subdividing the heavy mass of the atomic nucleus like uranium.

The nuclear fusion basically violate the law (Conservation of mass). During the nuclear fusion process the matter are not conserve because when the nuclei gets fuse then its mass are converted into the energy and then it is released.

ollegr [7]2 years ago

5 0

The mass lost in the nuclear reaction is all converted to energy.

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Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.

Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

$Q_1 = Q_2$

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

$Q = VA$

Where

V = Velocity

A = Cross-sectional Area

Our values are given as

$Q_2 = 1.2*10^{-4}m^3/s$

$d = 0.021m$

$r = \frac{0.021}{2} = 0.0105m$

Since there is continuity we have now that,

$V_1A_1 = Q_2$

$V_1A_1 = 1.2*10^{-4}$

$V_1 = \frac{1.2*10^{-4}}{A_2}$

$V_1 = \frac{1.2*10^{-4}}{\pi r^2}$

$V_1 = \frac{1.2*10^{-4}}{\pi (0.0105)^2}$

$V_1 =0.347m/s$

Therefore the speed of the water's house supply line is 0.347m/s

7 0

2 years ago

Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23

Sloan [31]

Answer:

The ratio is $\frac{T_1}{T_2} = 3.965$

Explanation:

From the question we are told that

The radius of Phobos orbit is R_2 = 9380 km

The radius of Deimos orbit is $R_1 = 23500 \ km$

Generally from Kepler's third law

$T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }$

Here M is the mass of Mars which is constant

G is the gravitational constant

So we see that $\frac{ 4 * \pi^2 }{G * M } = constant$

$T^2 = R^3 * constant$

=> $[\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3$

Here $T_1$ is the period of Deimos

and $T_1$ is the period of Phobos

$[\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}$

=> $\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]$

=> $\frac{T_1}{T_2} = 3.965$

8 0

2 years ago

A man exerts a force on a large couch by pushing on it. Which of the following must be a true statement about the couch after he

Elanso [62]

Answer: the answer is c

Explanation:

4 0

2 years ago

The absence of any mechanical linkage between the throttle pedal and the throttle body requires the use of a _______ motor.

Rom4ik [11]

The answer is A.

hope it helps :)

8 0

2 years ago

A small house was built on an island off a perfectly straight shoreline. The point B on the shoreline that is closest to the isl

abruzzese [7]

Answer:

Q should be 4.8 miles east of B.

Explanation:

As the diagram shows, we can simply express the construction cost as a function of angle θ (represented in the diagram).

The length of the pipe in water (represented with blue) = 6/cos θ

The length of the pipe on land (represented with brown) = (8-6*tan θ)

Construction Cost = (6/cos θ) (6000) + (8-6*tan θ)(3750)

The above function represents the construction cost and is in terms of θ

The value of θ varies from 0 degrees to 53.13 degrees as per the diagram.

We can take the derivative of Construction Cost function with respect to θ and equate it to zero to find the angle θ at which the construction cost is minimum.

d(Construction Cost)/d θ = -4500(5*sec θ – 8*tan θ)(sec θ)

-4500(5*sec θ – 8*tan θ) (sec θ) = 0

θ = 38.68 degrees

Using the value of θ, we can find the distance of Q from B.

Distance of Q from B = 6*tan θ

Distance of Q from B = 6*tan (38.68 degrees)

Distance of Q from B = 4.8 miles

7 0

2 years ago