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34kurt
2 years ago
15

The built-up beam is formed by welding together the thin plates of thickness 5 mm. determine the location of the shear center o.

Physics
1 answer:
atroni [7]2 years ago
4 0

Answer:

The location of the shear center o is 0.033 or 33 m

Explanation:

Solution

Recall that,

The moment of inertia of the section is =  I = 0.05 * 0.4 ^3 /12 + 0.005 * 0.2 ^3/12

= 30 * 10 ^ ⁻⁶ m⁴

Now,

The first moment of inertia is

Q =ῩA = [ (0.1 -x) + x/2] (0.005 * x)

= 0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²

Thus,

The shear flow is,

q =  VQ/I

so,

P =  (0.5x * 10 ^⁻³ - 2.5 x * 10⁻³ x²)/ 30 * 10 ^⁻⁶

P = (16.67 x - 83. 33  x²)

The shear force resisted by the shorter web becomes

Vw,₂ = 2∫ = ₀.₁ and ₀ = P (16.67 x - 83. 33  x²) dx = 0.11x

Then,

We take the moment at a point A

∑Mₐ = 0

- ( p * e)- (Vw₂ * 0.3 ) = 0

e =  0.11 p * 0.3/p

which gives us 0.033 m

= 33 m

Therefore the location of the shear center o is 0.033 or 33 m

Note: Kindly find an attached diagram to the question given above as part of the explanation solved with it.

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m=7800\times 1.41\times 10^{-6}\ kg/m

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2 years ago
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A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and
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Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

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Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

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2 years ago
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Answer:

a) 14.2 atm

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PV = nRT

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V = volume occupied by the gas

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R = molar gas constant = 0.08206 L.atm/mol.K

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Then the total vertical distance is ...

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2 years ago
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