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creativ13 [48]
2 years ago
13

Shi et al. (2013) measured the diffusivity of fluorescein (MW = 332), a fluorescent tracer, in the porcine temporomandibular joi

nt (TMJ) disk using a technique known as fluorescence recovery after photobleaching (FRAP). The TMJ disk consists mostly of water and a large amount of type I collagen. The overall average diffusivity of fluorescein in the TMJ disk was found to be 57.0 μm2 s−1. Using the Brinkman model, estimate the value of κ for fluorescein diffusion in the porcine TMJ disk.
Engineering
1 answer:
Sveta_85 [38]2 years ago
3 0

Answer:

The accuracy of survey radiographs in the diagnosis of acute thoracolumbar disc disease in 36 Dachshunds was determined by comparison with lumbar myelographic findings using iohexol. The value of making radiographs immediately after injection of contrast medium and the effectiveness of oblique radiographs in determining the exact circumferential distribution of extruding or protruding disc material were assessed. The presence of a double contrast medium column, resistance to injection and the presence of cerebrospinal fluid flow during needle placement was also evaluated. The location of the affected disc was accurately determined on survey radiographs in only 26 dogs. The myelographic technique used in this study resulted in the correct intervertebral space being identified, together with the exact circumferential distribution of disc material, in 35 dogs. Survey radiographs alone are inadequate for localization of protruding or extruding disc material

Explanation:

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22.5-4. Minimum Liquid Flow in a Packed Tower. The gas stream from a chemical reactor contains 25 mol % ammonia and the rest are
Firdavs [7]

Answer:

check attachments for answers

Explanation:

5 0
2 years ago
After a night of heavy rain, a thick coating of morning fog has all but stopped the flow of morning traffic. Which
Nat2105 [25]

Answer:

Weather Conditions

Explanation:

You cant see as well when driving through the fog

6 0
2 years ago
Read 2 more answers
Beryllium (Be) has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.568. If the radius of the Be atom is
sweet-ann [11.9K]

Answer:

Unit cell volume will be

4.866*10^{-2}nm^{3}

8 0
2 years ago
In a turning operation, spindle speed is set to provide a cutting speed of 1.8 m/s. The feed and depth of cut are 0.30 mm and 2.
love history [14]

Answer:

(a) shear plane angle (∅) = 33.53°

(b) shear strain (y) = 1.989

(c) material removal rate (MRR) = 1404mm³/s

Explanation:

Cutting speed = 1.8m/s

Feed = 0.3mm

Depth = 2.6mm

Angle = 8°

Thickness = 0.49

(a) calculating the chip thickness ratio using the formula;

r = t₀/tc

 = 0.3/0.49

 = 0.6122

Calculating the shear angle using the formula;

∅ = tan⁻¹[rcosα/1-rsinα]

  = tan⁻¹[(0.6122*cos8)/(1-0.6122sin8)]

  = 33.53°

(b) Calculating the shear strain using the formula;

y = cot∅ + tan(∅-α)

   = cot 33.53 + tan(33.53-8)

   = 1.509 + 0.477

  = 1.989

(c) Calculating the material removal rate using the formula;

MRR =f*d*V

        = 0.3 * 2.6 *1.8 *1000mm

        = 1404mm³/s

6 0
2 years ago
A railcar with an overall mass of 78,000 kg traveling with a speed vi is approaching a barrier equipped with a bumper consisting
sergij07 [2.7K]

Answer:

v₀ = 2,562 m / s  = 9.2 km/h

Explanation:

To solve this problem let's use Newton's second law

              F = m a = m dv / dt = m dv / dx dx / dt = m dv / dx v

              F dx = m v dv

We replace and integrate

            -β ∫ x³ dx = m ∫ v dv

            β x⁴/ 4 = m v² / 2

We evaluate between the lower (initial) integration limits v = v₀, x = 0 and upper limit v = 0 x = x_max

        -β (0- x_max⁴) / 4 = ½ m (v₀²2 - 0)

         x_max⁴ = 2 m /β   v₀²

         

Let's look for the speed that the train can have for maximum compression

         x_max = 20 cm = 0.20 m

         

         v₀ =√(β/2m)   x_max²

Let's calculate

          v₀ = √(640 106/2 7.8 104)    0.20²

          v₀ = 64.05  0.04

          v₀ = 2,562 m / s

          v₀ = 2,562 m / s (1lm / 1000m) (3600s / 1h)

          v₀ = 9.2 km / h

5 0
2 years ago
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