Answer:
B. PhCHO
Explanation:
Every organic group shows a characteristic IR absorption at certain wavelength . With the help of these absorption spectra we can identify the group present on organic molecules .
The wave number of 2710 cm⁻¹ is absorbed by aldehyde bond stretching .
The wave number of 1705 cm⁻¹ is shown by conjugated aldehyde . So the most likely compound among given compounds is PhCHO .
Barfoed's test is a concoction test utilized for identifying the nearness of monosaccharides. It depends on the diminishment of copper(II) acetic acid derivation to copper(I) oxide (Cu2O), which frames a block red hasten.
Barfoed's reagent comprises of a 0.33 molar arrangement of unbiased copper acetic acid derivation in 1% acidic corrosive arrangement. The reagent does not keep well and it is, thusly, fitting to make it up when it is really required. May store uncertainly as per a few MSDS's.
Answer:
The correct option is D.
Explanation:
Radioactive substances usually emit different types of particles when they are decaying. Such particles include alpha particles, beta particles and gamma ray. When an alpha particle is emitted from an unstable radioactive nucleus such nucleus usually lost an atomic mass that correspond to that of helium atom. Note that an alpha particle is made up of two protons and two neutrons, which result in mass number of 4. Thus, a nucleus that emit an alpha particle will have its mass number (atomic mass) reduce by 4 and atomic number that is reduced by 2.
Answer: The initial volume of the system is 60.29 L.
Explanation:
According to the first law of thermodynamics,
As it is given that heat is being added to the system so, 
will be positive. And, work done on the system is negative and work done by the system is positive.
So here, 
= -107.4 J
Q = 52.7 J
P = 0.693 atm
And, W = PdV
or, W = 
So, 
-107.4 J = 52.7 J - 0.693 \times 101.325 (63.2 - V)
-160.1 = -43.79 - 70.21 (63.2 - V)
63.2 - V = 
- V = 2.90 - 63.2
V = 60.29 L
Thus, we can conclude that the initial volume of the system is 60.29 L.
