Answer:
The distance is 6259.31 meters.
Explanation:
We shall use the Reyligh criterion to solve the problem
For diffraction due to circular aperture we have
Assuming that human eye is circular we have
Applying the given values we have
To understand how to use the principle of superposition in conjunction with the Biot-Savart (or Ampere's) law. From the Biot-Sav
art law, it can be calculated that the magnitude of the magnetic field due to a long straight wire is given by Bwire=μ0I2πd , where μ0 (=4π×10−7T⋅m/A) is the permeability constant, I is the current in the wire, and d is the distance from the wire to the location at which the magnitude of the magnetic field is being calculated. The same result can be obtained from Ampere's law as well.
1 answer:
Note: The Question Continues as
...Point L is located a distance d from the midpoint between the two wires. Find the magnitude of the net magnetic field BL created by pint L by both wires.
Express your answer in terms of I, d and appropriate constants.
2- The Figure is attached in the attachment.
Answer:
Find the attachment for complete solution
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The work done on the barbell is -165.62 Nm.
Explanation:
Work done on any object is the measure of force required to move that object from one position to another. So it is determined by the product of force acting on the object with the displacement of the object.
In the present problem, the displacement of the object on acting of force is given as 1.3 m. And the weight of the object which is a barbel is given as 13 kg. As the work is to lift the object from the ground, so the acceleration due to gravity will be acting on the object. In other words, the force applied on the object to lift it should be in opposite direction to the acting of acceleration due to gravity.
Thus,
Now, the force is -127.4 N and the displacement is 1.3 m.
So,
So, the work done on the barbell is -165.62 Nm.
Answer:
= 22.41rad/s
Explanation:
First, we know that:
a = 4 rad/s^2
S = 10 rev = 62.83 rad
Now we know that:
where is the final angular velocity,
the initial angular velocity, a is the angular aceleration and S the radians.
Replacing, we get:
Finally, solving for :
= 22.41rad/s
Answer:
The horizontal distance x between the two balloons is 54.15 m
Explanation:
The diagram described as obtained online is presented in the image attached to this solution.
Let the horizontal distance between the two balloons be x
Difference in height (vertical distance) between the two balloons = 61 - 48.2 = 12.8 m
Using trigonometric relations, it is evident that
Tan 13.3° = 12.8/x
x = 12.8/tan 13.3° = 12.8/0.2364 = 54.15 m
