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yuradex [85]
2 years ago
4

If the acetylene tank contains 37.0 mil of C2H2 and the oxygen tank contains 81.0 mol of O2, what is the limiting reactant for t

his reaction
2C2H2(l)+502(g) 4CO2(g)+2H2O(g)
Chemistry
1 answer:
dangina [55]2 years ago
6 0

Answer:

Explanation:

2C₂H₂(l)  +  50₂(g) =   4CO₂(g)  +  2H₂O(g)

2 mol          5 mol

2 mol of C₂H₂ reacts with 5 mol of O₂

37 mol of C₂H₂  will require 5/2 x 37 mol of O₂

= 92.5 mol of O₂

But oxygen available is only 81 mol so formation of product will be controlled by oxygen available . Hence oxygen is the limiting factor.

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5 0
2 years ago
Unit Conversion Help Thank you
AlekseyPX

Answer : 1721.72 g/qt are in 18.2 g/cL

Explanation :

As we are given: 18.2 g/cL

Now we have to convert 18.2 g/cL to g/qt.

Conversions used are:

(1) 1 L = 100 cL

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(3) 1 qt = 946 qt

The conversion expression will be:

\frac{18.2g}{1cL}\times \frac{100cL}{1L}\times \frac{1L}{1000mL}\times \frac{946mL}{1qt}

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5 0
2 years ago
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