Electromagnetic radiation is emitted when a charged particle moves through a medium faster than the local speed of light. This r
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Answer:
a) E=228391.8 N/C
b) E=-59345.91N/C
Explanation:
You can use Gauss law to find the net electric field produced by both line of charges.
Where E1 and E2 are the electric field generated at a distance of r1 and r2 respectively from the line of charges.
The net electric field at point r will be:
a) for y=0.200m, r1=0.200m and r2=0.200m:
b) for y=0.600m, r1=0.600m, r2=0.200m:
Answer:
It will sink
Explanation:
An object in the water can float only if its density is lower than the density of the water.
In fact, for an object completely immersed in water, there are two forces acting on it:
- Its weight, , downward, where
is the density of the object, V its volume and g the gravitational acceleration
- The buoyant force, , upwards, there
is the density of the water
We see that when the density of an object is larger than the density of the water, , the weight is greater than the buoyant force,
, so the object sinks.
In this case, the rock has a density of 1.73 g/cm3, while water has a density of 1.0 g/cm^3, so the rock will sink.
Answer:
600 Ω
Explanation:
when there is no load attached to the generator the circuit is open and zero current flows through the circuit, hence voltage drop across the internal resister is zero.
when 600Ω load is connected current starts flowing through the circuit and some voltage will drop across the internal resister.
voltage across the load resister is 1 V, so the current through it will be:
I=V/R
I=1/600 A= 1.67mA
voltage drop in the internal resister is:
V= input voltage - output voltage
V=2 V-1 V
⇒V=1 V
Now by using ohm's law
R=V/ I
R= (I= 1.67mA, as the resistors are connected in series)
⇒R=600 Ω
Hence Thevinin resistance of the generator is 600Ω.