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BartSMP [9]
2 years ago
14

What do you notice about the three lines reflected from the convex mirror?

Physics
1 answer:
NemiM [27]2 years ago
5 0

Answer:

They are reflected back at the same angle they came in

Explanation:

When parallel light rays hit a convex mirror they reflect outwards and travel directly away from an imaginary focal point (F). Each individual ray is still reflecting at the same angle as it hits that small part of the surface.

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Luke investigated the heating of water
Natali5045456 [20]
Amazingly awesome !
Go Luke !
See Luke investigate !
Water, water, water.
Heat, heat, heat.
Luke rocks !
He probably learned something.
3 0
2 years ago
The system consists of a 20-lb disk A, 4-lb slender rod BC, and a 1-lb smooth collar C. If the disk rolls without slipping, dete
dlinn [17]

Answer:

The velocity of the collar will be 3.076 ft/s

Explanation:

Given data

weight of the disk, Wa = 20lb

weight of rod BC, Wbc = 4lb

weight of collar, Wc = 1lb

Considering the equation of equilibrium

Vb = 1.5Wbc

Wa = 1.875 Wbc

to calculate the velocity of the collar using energy conservation equation

T1 + V1 = T2 + V2

0+4(1.5 \sin 45)+2(3 \sin 45)=\frac{1}{2}\left(\frac{1}{2}\left(\frac{20}{32.2}\right)(0.8)\right)              

=>(1.875 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)(1.5 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)

=>(1.5 W b c) \frac{1}{2}\left\{\frac{1}{12}\left(\frac{4}{32.2}\right)(3)\right\}+\frac{1}{2}\left(\frac{1}{32.2}\right)

=>(2.598 W b c)+4(1.5 \sin 0)+2(3 \sin 0)

Wbc = 1.18rad/sec

i.e.                                    

V _c=2.598 \times 1.18

= 3.076 ft/ s

5 0
2 years ago
What is the depth of the crater if the time is 6.3 s? An astronaut stands by the rim of a crater on the moon, where the accelera
ollegr [7]

Complete Question

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it

to hit the bottom. If the time is 6.3 s, what is the depth of the crater?

Answer:

The depth is 32 m

Explanation:

From the question we are told that

  The  time is  t =  6.3 s

  The acceleration due to gravity is  g =  1.62 \  m/s^2

 

Generally from kinematic equation

    s = ut + \frac{1}{2}  - at^2

Here the u is the initial  velocity and the value is  0 m/s

      s = 0 + \frac{1}{2}  - (1.62) * (6.3)^2

        s = 32 \ m

   

8 0
2 years ago
. Imagine that you are standing at the center of a giant bowl of gelatin. What type of wave will you make across the top of the
vichka [17]
Transverse wave as the wave is going up and down no compressions
3 0
2 years ago
A single slit diffraction experiment performed with an argon laser of wavelength 454.6 nm produces a pattern on a screen with da
tankabanditka [31]

To develop this problem it is necessary to apply the concepts related to Interference and the Two slit experiment.

Young's equation defines the separation between fringes this phenomenon as,

d = \frac{\lambda D}{a}

Where,

\lambda = Wavelength

d = Separation between fringes

a =  Slit width

D = Distance between the slits and screen

Then for the two case we have

d_1 = \frac{\lambda D}{a_1}

d_2 = \frac{\lambda D}{a_2}

Calculating the new separation between the fringes would be

\frac{d_2}{d_1} = \frac{\frac{\lambda D}{a_1}}{\frac{\lambda D}{a_2}}

\frac{d_2}{d_1} = \frac{\lambda_1}{\lambda_2}

d_2= \frac{\lambda_1}{\lambda_2} d_1

We have then,

d_2 = \frac{632.9*10^{-8}}{454.6*10^{-9}} 10*10^{-3}

d_2 = 13.9mm

Therefore the correct answer is c.

7 0
2 years ago
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