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Ipatiy [6.2K]
2 years ago
4

A 38.5 kg man is in an elevator

Physics
1 answer:
Fiesta28 [93]2 years ago
8 0

Answer:

F = m*(g - a) →

a = g - F/m = 0.891 m/s² downward

Explanation:

If elevator was stationary, the normal force of elevator floor on man* would be = mg

mg = (38.5)(9.81) ≈ 378 N.

If elevator is accelerating downward the floor is accelerating away from man and so the normal force will be less than man's weight by: 378 - 343 = 35 N.

<em><u>Hope this helps.</u></em>

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Answer:

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I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx
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