answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aalyn [17]
2 years ago
8

A car traveling on a level road initially has 440 kJ of mechanical energy. After the brakes are applied for a few seconds, the c

ar has only 110 kJ of mechanical energy. What best accounts for the missing mechanical energy? In other words, where did that missing energy go?
Physics
1 answer:
ki77a [65]2 years ago
8 0

Answer:

The missing mechanical energy becomes thermal energy in form of heat transferred to the medium (air and ground)

Explanation:

When the car applies the brakes, the friction between wheels and highway generates heat. This heat is transmitted to the air and to the ground.

Then, part of the mechanical energy of the car becomes thermal energy in form of heat.

The car, at the beginning has a energy of 440kJ, after the brakes are applied, the car has 110 kJ of energy. This means that necessarily the car loos 330 kJ of energy that became heat to the medium (air and ground)

You might be interested in
1. A student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.
Snezhnost [94]

Explanation:

(a) Displacement of an object is the shortest path covered by it.

In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.  She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

(b) Average velocity = total displacement/total time

t = 15 min = 0.25 hour

v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h

Hence, this is the required solution.

8 0
2 years ago
If you lived on Saturn, which planets would exhibit retrograde motion like that observed for Mars from Earth? (Select all that a
liberstina [14]

Answer:

a) Earth

b) Mercury

c) Neptune

Explanation:

All the planets move around the sun in eastward direction, but few planet have retrograde rotation i.e in westward direction. Retrograde motion is just an apparent change in the movement of planet which means it only seems as if the planet are rotating in opposite direction. Retrograde movement of planet like  Saturn, Jupiter and mars is not real. Hence, if a person lives on Saturn, then following planets will exhibit retrograde motion  

a) Earth

b) Mercury

c) Neptune

4 0
2 years ago
Brass is an alloy made from copper and zinc a 0.59 kg brass sample at 98.0 is dropped into 2.80 kg of water at 5.0 c if the equi
zhannawk [14.2K]
The specific heat capacity of brass would be ranked between 0 and infinity
3 0
2 years ago
Read 2 more answers
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
2 years ago
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.240 rev/s. The magnitude
bazaltina [42]

Explanation:

Given that,

Angular velocity = 0.240 rev/s

Angular acceleration = 0.917 rev/s²

Diameter = 0.720 m

(a). We need to calculate the angular velocity after time 0.203 s

Using equation of angular motion

\omega_{f}=\omega_{i}+\alpha t

Put the value in the equation

\omega_{f}=0.240+0.917\times0.203

\omega_{f}=0.426\ rev/s

The angular velocity is 0.426 rev/s.

(b). We need to calculate the tangential speed of the blade

Using formula of  tangential speed

v= r\omega

Put the value into the formula

v = \dfrac{0.720 }{2}\times0.426\times2\pi

v=0.963\ m/s

The tangential speed of the blade is 0.963 m/s.

(c). We need to calculate the magnitude at of the tangential acceleration

Using formula of tangential acceleration

a_{t}=r\alpha

Put the value into the formula

a_{t}=0.36\times0.917\times2\pi

a_{c}=2.074\ m/s^2

The tangential acceleration is 2.074 m/s².

Hence, This is required solution.

4 0
2 years ago
Other questions:
  • What voltage is delivered to a 120-volt/5,000-watt load that is fed with #10 awg wire (1.24 ohms/1,000 feet) and located 750 fee
    8·1 answer
  • A ray of light is incident on a plane surface separating two sheets of glass with refractive indexes 1.70 and 1.58. The angel of
    7·2 answers
  • In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t
    8·1 answer
  • Temperature and kinetic energy are ___________ proportional. adirectly directly indirectly 2. Heat is a measure of _____________
    15·2 answers
  • Fill in the terms that accurately complete the statements. The nucleus contains positively charged particles called and neutral
    11·2 answers
  • Chose the word that correctly completes the following sentence: Kirchoff's junction law expresses the conservation of ____. a) m
    15·1 answer
  • The figure above represents a stick of uniform density that is attached to a pivot at the right end and has equally spaced marks
    13·1 answer
  • A solid uniform sphere of mass 1.85 kg and diameter 45.0 cm spins about an axle through its center. Starting with an angular vel
    15·2 answers
  • A positively charged particle Q1 = +45 nC is held fixed at the origin. A second charge Q2 of mass m = 4.5 μg is floating a dista
    10·1 answer
  • Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!