Answer:
Explanation:
Pressure is measured is here p is pressure
is density and h is height
We have given pressure acceleration due to gravity
height =1.163 m
A coaxial cable consists of a thin insulated straight wire carrying a current of 2.00 A surrounded by a cylindrical conductor ca
1 answer:
Answer:
B = 15μT
Explanation:
In order to calculate the magnitude of the magnetic field generated by the coaxial cable you use the Ampere's law, which is given by:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
I: current
r: distance from the wire to the point in which B is calculated
In this case you have two currents with opposite directions, which also generates magnetic opposite magnetic fields. Then, you have (but only for r > radius of the cylindrical conductor) the following equation:
(2)
I1: current of the central wire = 2.00A
I2: current of the cylindrical conductor = 3.50A
r: distance = 2.00 cm = 0.02 m
You replace the values of all parameters in the equation (2), and you use the absolute value because you need the magnitude of B, not its direction.
The agnitude of the magnetic field outside the coaxial cable, at a distance of 2.00cm to the center of the cable is 15μT
You might be interested in
Complete Question
The complete Question is shown on the first uploaded image
Answer:
a
The torque acting on the particle is
b
The magnitude of the angular momentum increases relative to the origin
Explanation:
From the equation we are told that
The position of the particle is
The mass of the particle is
The time is t
The torque acting on the particle is mathematically represented as
where is change in angular momentum which is mathematically represented as
Where X mean cross- product
is the velocity which is mathematically represented as
Substituting for
Now the cross product of is mathematically evaluated as
So the angular momentum becomes
Substituting for m
Substituting into equation for torque
The magnitude of the angular momentum can be evaluated mathematically as
From the is equation we see that the magnitude of the angular momentum is varies directly with square of the time so it would relative to the origin because at the origin t= 0s and we move out from origin t increases hence angular momentum increases also
Answer:
Explanation:
Given that,
The radius of sphere, r = 0.3 m
Distance from the center of the sphere to the point P, x = 0.5 m
Electric field at point P, (radially outward)
The maximum electric field is at the surface of the sphere. We know that the electric field is inversely proportional to the distance. So,
So, the magnitude of the electric field due to this sphere is 41666.66 N/C. Hence, this is the required solution.
Complete Question
The complete question is shown on the first uploaded image
Answer:
Force on each hand is 196.22 N
Force on each foot is 95.8 N
Explanation:
In order to get a better understanding of this question let us explain some concepts
Normal Force:
We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.
Torque:
We can define torque as the moment of forces that tends to produce or cause rotation
From the question we are given that
Weight of body is (W) = 584 N
The normal force on both hands (Ha) = ?
The normal force on both legs (Lg) = ?
Looking at the diagram the person is at equilibrium so
584 = Ha + Lg
an also this mean that torques acting on the body is balanced
So, 0.410 Ha = 0.840 Lg
Making Lg the subject of formula in the equation above we
Lg = 0.4881 Ha
Considering the first equation and replacing Lg with this recent equation we have
584 = Ha + 0.4881 Ha
Therefore Ha = 392.44 N
This value obtained is for both hands for each hand we divide by 2
Therefore we have for each hand =196.55 N
Since we have been able to get the force on both hands we can substitute it in to the equation where we made Lg the subject of formula and we have
Lg = 0.4881 × 392.44
= 191.22 N
The value above is the force on both legs to obtain the force on each leg we have
191.22/2 = 95.8 N.
