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artcher [175]
2 years ago
11

Which statement represents how light travels? Light given off from a moving source will travel faster in a vacuum. Light given o

ff from a moving source will travel faster in air. Light travels slower if the light source is moving. Light travels at the same speed even if the light source is moving.
Physics
2 answers:
BartSMP [9]2 years ago
7 0

Answer:

Light travels at the same speed even if the light source is moving.

Explanation:

I took the test, hope this helps :)

Debora [2.8K]2 years ago
4 0

Answer:

the first one

Explanation:

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alex41 [277]

Answer:

The simplified expression is M  =  \frac{v^2 r}{G}

Explanation:

From the question we are told that  

     M  = \frac{ \frac{m v^2}{r} }{\frac{ mG}{r^2 } }

So simplifying we have

    M  =    \frac{m v^2}{r} *  \frac{r^2 }{ mG }

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Thus the simplified formula is M  =  \frac{v^2 r}{G}

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8.4-1 Consider a magnetic field probe consisting of a flat circular loop of wire with radius 10 cm. The probe’s terminals corres
Vlad1618 [11]

Answer:

B_o = 1.013μT

Explanation:

To find B_o you take into account the formula for the emf:

\epsilon=-\frac{d\Phi_b}{dt}=-\frac{dBAcos\theta}{dt}=-Acos\theta\frac{dB}{dt}

where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.

By applying the derivative you obtain:

\epsilon=-Acos\theta (2\pi f) B_ocos(2\pi f t+ \alpha)

when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:

\epsilon=2\pi fAB_o=2\pi (100*10^3Hz)(\pi (0.1m)^2)B_o=19739.20Hzm^2B_o\\\\B_o=\frac{20*10^{-3}V}{19739.20Hzm^2}=1.013*10^{-6}T=1.013\mu T

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2 years ago
(8%) Problem 9: Helium is a very important element for both industrial and research applications. In its gas form it can be used
exis [7]

Answer:

2046.37 kPa

Explanation:

Given:

Number of moles, n = 125

Temperature, T = 20° C = 20 + 273 = 293 K

Radius of the cylinder, r = 17 cm = 0.17 m

Height of the cylinder, h = 1.64 m

thus,

volume of the cylinder, V = πr²h

= π × 0.17² × 1.64

= 0.148 m³

Now,

From the ideal gas law

we have

PV = nRT

here,

P is the pressure

R is the ideal gas constant = 8.314  J / mol. K

thus,

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or

P × 0.148 = 304500.25

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pentagon [3]

I'm assuming you want the first law of thermodynamics.

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