The answer to your question would be _B High Temp
<span>We breathe around an average of 500 ml of air in 1 normal (or relax) breathing. The lungs already have around 3 litres of reserve breathing. Since there is around 21% oxygen in air, we breathe in around 105 ml of Oxygen from the air. That is equal to around 0.14 g of Oxygen.</span>
First lets calculate the moles of aluminum (molar mass is 27 gram/mol):
n = m/M = 14.9 / 27 = 0.551 mole of Al
According to the reaction between sulfuric acid and aluminum:
From 2 moles of aluminum ==> we get 3 moles of Hydrogen gas
so, let's do cross multiplication
0.551 ==> 0.551 * 3/2 = 0.83 mole of H2
So, from this reaction we got 0.83 mole of H2 gas
knowing that the molar mass of H2 is 2 gram/mol, the mass of the gas is.
m = n * M = 0.83 * 2 = 1.66 gram of H2
Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound should be neutral; the overall charge of it is equal to zero.
- Binary ionic compound is composed of two different ions.
<u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.
- CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.
- VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.
<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.</em>
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