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djverab [1.8K]
2 years ago
9

when switch s is closed positive ions will undergo 1) oxidation at electrode B 2) oxidation at electrode A 3) reduction at elect

rode B 4) reduction electrode A
Chemistry
1 answer:
stepladder [879]2 years ago
4 0

Answer:

reduction at electrode B

Explanation:

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What is the mass of 2.5 moles of hydrogen fluoride gas HF
Nady [450]

Answer:

You will get 5.0 g of hydrogen.

Explanation:

As with any stoichiometry problem, we start with the balanced equation.

Sn

l

+

2HF

→

SnF

2

+

H

2

Moles of H

2

=

2.5

mol Sn

×

1 mol H

2

1

mol Sn

=

2.5 mol H

2

Mass of H

2

=

2.5

mol H

2

×

2.016 g H

2

1

mol H

2

=

5.0 g H

2

7 0
2 years ago
Formulating an Investigative Question In this experiment, you will use a track and a toy car to explore the concept of movement.
Solnce55 [7]

Answer:

A scientific question to be asked is; <em>What is the average speed of the toy car?</em>

Explanation:

A scientific question is a question which is well defined, the values in the question can be measured, and the inputs and outputs related to the question are controllable

The parameters measured in the experiment are;

The time elapsed during the movement of the car, <em>Δt</em>

The distance the car moves, <em>d</em>

From the obtained measurements, the value can be calculated is the average speed of the toy car as follows;

The \ average \ speed \ of \ the \ toy \ car, \ v_{avg} = \dfrac{d}{\Delta t}

Therefore, a scientific question to be asked that will be answered by doing the experiment is; What is the average speed of the toy car?

3 0
2 years ago
A solution surrounding a cell is hypertonic solution if: a. It contains fewer nonpenetrating solute particles than the interior
arlik [135]

Answer:

The answer is B. It contains more non-penetrating solute particles than the interior of the cell.

Explanation:

This means that it has a greater concentration or number of solute particles outside a membrane than there are inside it.

A typical example is Saline solution.

8 0
2 years ago
Enter the net ionic equation representing solid chromium (iii) hydroxide reacting with nitrous acid. express your answer as a ba
Colt1911 [192]

The net ionic equation of chromium (iii) hydroxide reacting with nitrous acid:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

<h3>Further explanation</h3>

The electrolyte in the solution produces ions.

The equation of a chemical reaction can be expressed in the equation of the ions

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is a spectator ion that is the ion which does not change (does not react) because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as an ionized molecule

So only the dissolved compound is ionized ((expressed in symbol aq)

From the problem, it is stated that chromium (iii) hydroxide reacting with nitrous acid.

Reactions that occur:

Cr(OH)₃ (s) + 3HNO₂ (aq) ⇒ Cr(NO₂)₃ (aq) + 3H₂O (l)

Cr (OH)₃ solid form that does not decompose in the form of ions, as well as water (H₂O)

So the ionic equation becomes:

Cr(OH)₃ (s) + 3H⁺ (aq) + 3NO₂⁻ (aq) ⇒ Cr³⁺ (aq) + 3NO₂⁻ (aq) + 3H₂O (l)

There is an ion spectator that is 3NO₂⁻, so that if it is removed a net ionic equation will be formed:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

<h3>Learn more</h3>

the net ionic equation

brainly.com/question/11854070

brainly.com/question/10280219

brainly.com/question/9830467

Keywords: the net ionic equation, an ion spectator

5 0
2 years ago
Read 2 more answers
Consider the decomposition of the compound C5H6O3 as follows below. C5H6O3(g) → C2H6(g) + 3 CO(g) When a 5.63-g sample of pure C
timofeeve [1]

Answer:

K = 6.5 × 10⁻⁶

Explanation:

C₅H₆O₃ ⇄ C₂H₆ + 3CO

Use PV=nRT to find the initial pressure of C₅H₆O₃

P (2.50) = (0.0493) (0.08206) (473)

P = 0.78atm

C₅H₆O₃ ⇄ C₂H₆ + 3CO

0.78atm      0           0

0.78 - x        x           3x

1.63atm = 0.78 - x + x + 3x

P(total) = 0.288atm

C₅H₆O₃ = 0.78 - 0.288

             = 0.489atm

C₂H₆ = 0.288atm

CO = 0.846atm

K_p = \frac{0.288 * 0.864^3}{0.489}

     = 0.379

K = \frac{K_p}{RT^3}

K = \frac{0.379}{(0.0821 * 473)^3}

   = 6.5 × 10⁻⁶

7 0
2 years ago
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