Answer:
3-methylthiophene > thiophene > benzene > 2-methylfuran
Explanation:
Primarily, five membered heterocyclic aromatic rings undergo nitration at carbon-2. This is because, nitration at carbon-2 leads to the formation of three resonance structures while attack at carbon-3 yields only two resonance structures, hence it is less stabilized.
The presence of a methyl group which donates electrons promotes the stabilization of the cation formed in the nitration of 3-methylthiophene.
2-methylfuran is the least reactive towards nitration because the 2-position has been blocked by a methyl group.
Answer:
I believe it's false because the atomic number is the number of protons in the nucleus of an atom.
of octane had been converted to carbon dioxide CO₂.
<h3>Explanation</h3>
Octane has a molar mass of
1.000 gallon of this fuel would have a mass of 2.650 kilograms or 
, which corresponds to 
of octane.
Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:
An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:
The mass of the product mixture is 
heavier than that of the octane supplied. Thus 
of oxygen were consumed in the combustion. There are 
of oxygen molecules in 
of oxygen.
Let the number of moles of octane that had undergone complete combustion as seen in the first equation be 
(
). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal 
.
25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.
Therefore 
out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.
Hello!
To find the amount of atoms that are in 80.45 grams of magnesium, we will need to know Avogadro's number and the mass of one mole of magnesium.
Avogadro's number is 6.02 x 10^23 atoms, and one mole of magnesium is equal to 24.31 grams.
1. Divide by one mole of magnesium
80.45 / 24.31 = 3.309 moles (rounded to the number of sigfigs)
2. Multiply moles by Avogadro's number
3.309 x (6.02 x 10^23) = 1.99 x 10^24 (rounded to the number of sigfigs)
Therefore, there are 1.99 x 10^24 atoms in 80.45 grams of magnesium.
Answer: b. pressure
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
(At constant volume and number of moles)
where,
= initial pressure of gas = p
= final pressure of gas = ?
= initial temperature of gas = t
= final temperature of gas = 2t
Thus the pressure also doubles when absolute temperature is doubled.
