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valkas [14]
2 years ago
3

3.) [15 points] A physics teacher is on the west side of a small lake and wants to swim across and up at a point directly across

from his starting point. He notices that there is a current in the lake and
that a leaf floating by him travels 4.2m [S] In 5.0s. He is able to swim 1.9 m/s in calm water,
(a) What direction will he have to swim in order to arrive at a point directly across from his position?​
Physics
1 answer:
Sveta_85 [38]2 years ago
3 0

Answer:

The teacher should swim in a direction 29.24° North of East

Explanation:

Given that the there is a water  current across the lake, and the physics teacher intends to swim directly across the lake, the direction the physics teacher will have to swim is found as follows;

The speed of the water current is given by the speed of the floating leaf traveling with the water current  

Distance traveled by the leaf = 4.2 m South

Time of travel of the leaf = 5.0 s

Speed of leaf = 4.2/5 = 0.84 m/s = Speed of the water current

Swimming peed of the teacher, v = 1.9 m/s

To swim directly across the lake, the teacher has to swim slightly in the opposite direction of the water current, the y-component of the teacher's swimming speed should be equal to and opposite that of the speed of the water current.

Y-component of v = v×sin(θ), where θ is the angle of the direction, the teacher should swim

Therefore;

1.9 × sin(θ) = 0.84

sin(θ) = 0.84/1.9 = 0.44

θ = 26.24°

That is the teacher should swim in a direction 29.24° North of East.

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Fill in the blanks to complete each statement about weathering. Weathering is the breakdown of rocks into smaller particles call
nevsk [136]

Answer:

sediments

Explanation:

Weathering is the breakdown of rocks into smaller particles called:

                 sediments

Weathering is the physical disintegration and chemical decay of rocks into smaller fragments to produce sediments. The product of rock weathering is basically sediments. Some of the sediments can be transformed to form soils when they combine with organic matter, water and air.

Physical weathering is when rocks are physically broken into smaller pieces, but the minerals in  the rock remain the same.

             Physical weathering

Physical weathering is the disintegration of rocks into smaller bits without altering the chemical make up of the minerals. The goal of physical weathering is to expose rock surface to action of chemical weathering.

When a rock is broken down in a way that changes the mineral composition, it is called  chemical weathering

          chemical weathering

Chemical weathering is the decay of rocks by altering the minerals in a rock.

Hope this Helps! c:

8 1
2 years ago
Read 3 more answers
A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m
Marrrta [24]

Answer:

-1.47 m/s^2

Explanation:

We can use the following SUVAT equation to solve the problem:

v^2 - u^2 = 2ad

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

a=\frac{v^2-u^2}{2d}=\frac{0-(24)^2}{2(196)}=-1.47 m/s^2

4 0
2 years ago
A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act lik
Lady bird [3.3K]

Answer:

The options are approximations of the exact answers:

A) 1\times10^6N/C

B) 2\times10^{-13}N

C) 1\times10^{-2}V

D) Toward the inner wall

E) 3\times10^{-17}J

Explanation:

A) The electric field in a parallel plate capacitor is given by the formula E=\frac{\sigma}{k\epsilon_0}, where \epsilon_0=8.85\times10^{-12}C/Vm and in our case \sigma=10^5C/m^2 and, for air,k=1.00059, so we have:

E=\frac{10^5C/m^2}{(1.00059)(8.85\times10^{-12}C/Vm)}=1.13\times10^6N/C

B) The K+ ion has one elemental charge excess, so its charge is q=1.6\times10^{-19}C, and the force a charge experiments under an electric field E is given by F=qE, so we have:

F=(1.6\times10^{-19}C)(1.13\times10^6N/C)=1.81\times10^{-13}N

C) The potential difference between two points separated a distance d under an uniform electric potential E is given by \Delta V=dE, so we have:

\Delta V=(10\times10^{-9}m)(1.13\times10^6N/C)=1.13\times10^{-2}V

D) The electic field goes from positive to negative charges, so it goes towards the inner wall.

E) The work done by an electric field through a potential difference \Delta V on a charge Q is W=Q\Delta V, and is equal to the kinetic energy imparted on it, so we have:

K=(3\times10^{-15}C)(1.13\times10^{-2}V)=3.39\times10^{-17}J

5 0
2 years ago
A simple pendulum 0.64m long has a period of 1.2seconds. Calculate the period of a similar pendulum 0.36m long in the same locat
weqwewe [10]

The period of the second pendulum is 0.9 s

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity at the location of the pendulum

For the first pendulum, we have

L = 0.64 m

T = 1.2 s

Therefore we can find the value of g at that location:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{1.2})^2 (0.64)=17.5 m/s^2

Now we can find the period of the second pendulum at the same location, which is given by

T=2\pi \sqrt{\frac{L}{g}}

where we have

L = 0.36 m (length of the  second pendulum)

g=17.5 m/s^2

Substituting,

T=2\pi \sqrt{\frac{0.36}{17.5}}=0.9 s

#LearnwithBrainly

8 0
2 years ago
A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

3000²)

A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

5 0
2 years ago
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