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larisa86 [58]
2 years ago
13

A tiling company completes two jobs. The first job has $1200 in labor expenses for 40 hours worked, while the second job has $15

60 in labor expenses for 52 hours worked. The relationship between the labor expenses and the hours worked is linear. Which equation can be used to calculate the y-intercept of the linear equation? 1200 = 40 (40) + b 1560 = 30 (40) + b 1560 = 30 (52) + b 1200 = 52 (30) + b
Mathematics
1 answer:
daser333 [38]2 years ago
6 0

Answer:

The correct option is;

1560 = 30(52) + b

Step-by-step explanation:

The cost of the first job = $1,200 in labor and expenses

The number of hours worked in the first job = 40

The second job costs $1,560 in labor and expenses

The number of hours worked in the second job = 52

If the cost of labor per hour = L and the expenses = b, we have;

$1,200 = 40×L + b......................(1)

$1,560 = 52×L + b.......................(2)

Subtracting equation (1) from (2), we have;

52×L + b - (40×L + b) =  52×L - 40×L + b - b = $1,560 - $1,200 = $360

12×L = $360

L = $360/12 = $30/hour

From equation (1), we have;

$1,200 = 40×L + X =  40×$30 + b

Therefore, the equation that can be used to calculate the y-intercept of the linear equation is either;

1200 = 40(30) + X or 1560 = 32(52) + b, which gives the correct option as 1560 = 32(52) + b

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Step-by-step explanation:

Given:

Mass of Sodium citrate = 5 g

Mass of Tartar Emetic = 0.015 g = 15 mg

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sensitivity = 4 mg

Error = 5%

Now,

The smallest weight that can be measured = \frac{\textup{Sensitivity}}{\textup{Error}}\times100

or

The smallest weight that can be measured =  \frac{\textup{4}}{\textup{5}}\times100  = 80 mg

Now,

80 mg is dissolved in 120 mL of Cherry syrup according to prescription

( Thus,

1 mg is dissolved in \frac{120}{80}\ mL  of Cherry syrup according to prescription )

so to measure 15 mg of Tartar Emetic, measure the volume of cherry syrup

=   15\times\frac{120}{80}\ mL

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Hence, the correct quantity of tartar emetic to fill the prescription will be obtained

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The value of 86º in radians is:

86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi

86^{\circ} = \frac{43}{90}\pi\,rad

Then, the cosine of 86º is:

\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}

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Answer:

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Step-by-step explanation:

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