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Mrac [35]
2 years ago
15

The distance from the center of a lens to the location where parallel rays converge or appear to converge is called the _____ le

ngth.
Physics
1 answer:
Morgarella [4.7K]2 years ago
7 0

Answer:

<h2>FOCAL</h2>

Explanation:

<em>The center of a lens is known as its optical center. </em><em>All light rays incident on a particular lens converges at a points a point known as the principal focus or the focal point after reflecting</em><em>. Note that all light incident on a reflecting surface must all converge at this focal point after reflection. </em>

The distance measured from the center of this lens to its principal focus (otherwise known as focal point) is known as the <em>focal length of the lens. </em>

<em>Based on the explanation above, it cam be concluded that the distance from the center of a lens to the location where parallel rays converge or appear to converge is called the</em><em> FOCAL</em><em> length.</em>

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Multiply the number 4.48E-8 by 5.2E-4 using Google. What is the correct answer in scientific notation?
Oksi-84 [34.3K]

Answer:

2.32\times 10^{-11}

Explanation:

First number is 4.48\times 10^{-8}

Second number is 5.2\times 10^{-4}

We need to multiply the two numbers.

4.48\times 10^{-8}\times 5.2\times 10^{-4}=(4.48\times 5.2)\times 10^{(-8-4)}\\\\=23.296\times 10^{-12}

In scientific notation : 2.32\times 10^{-11}

Hence, this is the required solution.

8 0
2 years ago
Enrico says that positive charge is created when you rub a glass rod with silk, and that negative charge is simply the absence o
lisabon 2012 [21]

Answer:5 Neither: both negative and positive charge are present simultaneously in all solid materials on Earth

Explanation:

When we rub a glass rod with silk cloth then some of the electrons from glass rods are stripped away to the silk cloth. These electrons are loosely bound to the silk rod that is why they easily transferred to silk cloth.  

There is no net charge because the charge is induced when we rub the cloth and charge are separated therefore we able to notice these charges.

7 0
2 years ago
If the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal
iVinArrow [24]

Answer:

xcritical = d− m1 /m2 ( L /2−d)

Explanation: the precursor to this question will had been this

the precursor to the question can be found online.

ff the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal bar may become unstable (i.e., the bar may no longer remain horizontal). What is the smallest possible value of x such that the bar remains stable (call it xcritical)

. from the principle of moments which states that sum of clockwise moments must be equal to the sum of anticlockwise moments. aslo sum of upward forces is equal to sum of downward forces

smallest possible value of x such that the bar remains stable (call it xcritical)

∑τA = 0 = m2g(d− xcritical)− m1g( −d)

xcritical = d− m1 /m2 ( L /2−d)

6 0
2 years ago
A device that uses electricity and magnetism to create motion is called a _________motor,magnet,generator . In a reverse process
lawyer [7]
A device that uses electricity and magnetism to create motion is called a "Motor" (which converts electric energy into mechanical energy) & <span>In a reverse process, a device that uses motion and magnetism can be used to create "Electromagnetism".

In short, 1st Blank = Motor
2nd Blank = Electromagnetism 

Hope this helps!</span>
5 0
2 years ago
Read 2 more answers
A carbon-dioxide laser emits infrared light with a wavelength of 10.6 μm. What is the length of a tube that will oscillate in th
alex41 [277]

Answer:

The length of a tube and number of rounds are 0.848 m and 1.77\times10^{8}\ trip\ per\ second.

Explanation:

Given that,

Wavelength \lambda= 10.6\mu m

m = 160000

We need to calculate the length

Using formula of wavelength

Laser tube behave like closed pipe

m\dfrac{\lambda}{2}=L

L=160000\times\dfrac{10.6\times10^{-6}}{2}

L=0.848\ m

Distance traveled by pulse of light in one back and fourth trip

d=2L

d=2\times0.848

d=1.696\ m

We need to calculate the time

Using formula for time

t = \dfrac{d}{c}

t=\dfrac{1.696}{3\times10^{8}}

t=5.653\times10^{-9}\ s

We need to calculate the number of round

Using formula of number of round

N=\dfrac{1}{t}

N= \dfrac{1}{5.653\times10^{-9}}

N=1.77\times10^{8}\ trip\ per\ second

Hence, The length of a tube and number of rounds are 0.848 m and 1.77\times10^{8}\ trip\ per\ second.

7 0
2 years ago
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