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2 years ago

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The left end of a long glass rod 6.00 cm in diameter has a convex hemispherical surface 3.00 cm in radius. The refractive index

of the glass is 1.60. Determine the position of the image if an object is placed in air on the axis of the rod at the following distances to the left of the vertex of the curved end:
(a) infinitely far,
(b) 12.0 cm;
(c) 2.00 cm.

1 answer:

Musya8 [376]2 years ago

5 0

Complete Question

The left end of a long glass rod 6.00 cm in diameter has a convex hemispherical surface 3.00 cm in radius. The refractive index of the glass is 1.60. Determine the position of the image if an object is placed in air on the axis of the rod at the following distances 1.00 cm to the left of the vertex of the curved end:

(a) infinitely far,

(b) 12.0 cm;

(c) 2.00 cm.

Answer:

The image distance is $v = 2 \ cm$

Explanation:

From the question we are told that

The diameter is $d = 6.0 \ cm = 0.06 \ m$

The radius of the convex hemisphere is $r = 3.0 \ cm = 0.03 \ m$

The refractive index is $n = 1.60$

The object distance is $u = 2.00 \ cm = 0.02 \ m$

The refractive index of air is $n_a = 1$

Generally lens maker's law is mathematically represented as

$\frac{n_a}{u} - \frac{n}{v} = \frac{(n - n_a )}{r}$

=> $\frac{1}{1} - \frac{1.60}{v} = \frac{(1.60 - 1 )}{3}$

=> $v = 2 \ cm$

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