(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her av
1 answer:
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Answer:
The magnitude of the resultant acceleration is 2.2
Explanation:
Mass (m) of the sailboat = 2000 kg
Force acting on the sailboat due to ocean tide is = 3000N
Eastwards means takes place along the positive x direction
Then = 3000N and
= 0
Wind Force acting on the Sailboat is = 6000N directed towards the northwest that means at an angle 45 degree above the negative x axis
Then
= -(6000N) cos 45 degree = -4242.6 N
= (6000N) cos 45 degree = 4242.6 N
Hence , the net force acting on the sailboat in x direction is
= - 3000 N + 4242.6 N
= - 3000 N +4242.6 N
= 1242.6N
Net Force acting on the sailboat in y direction is
= 0+ 4242.6N
= 4242.6N
The magnitude of the resultant force =
Using pythagorean theorm of 1243 N and 4243 N
4420.8 N
F = ma
=2.2
Answer:
aₓ = 0 , ay = -6.8125 m / s²
Explanation:
This is an exercise that we can solve with kinematics equations.
Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.
x axis
vₓ = v₀ₓ = 1.10 m / s
aₓ = 0
y axis
initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration
= v_{oy} -ay t
ay = (v_{oy} -v_{y}) / t
ay = (0 -10.9) / 1.6
ay = -6.8125 m / s²
the sign indicates that the acceleration goes in the negative direction of the y axis
Answer:
1027.2 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32.2 ft/s
The height the tomato would fall is 450+577.2 = 1027.2 m