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Dvinal [7]
2 years ago
4

Adapt the velocity equation v=v0 + at to solve for average acceleration where the ball starts at t = 0.0 seconds and v0 = 0.00 m

eters/second
Physics
2 answers:
Basile [38]2 years ago
5 0

Answer:

The adapted expression for average acceleration is a = \frac{v}{t'}.

Explanation:

Let be v = v_{o} + a\cdot t, which can be adapted by using the following substitution:

t = t'-t_{o}

Where:

t' - Final instant, measured in seconds.

t_{o} - Initial instant, measured in seconds.

v = v_{o}+a\cdot (t-t_{o})

Where:

v - Final velocity, measured in meters per second.

v_{o} - Initial velocity, measured in meters per second.

a - Average acceleration, measured in meters per square second.

Now, average acceleration is cleared:

a = \frac{v-v_{o}}{t'-t_{o}}

Given that t_{o} = 0\,s and v_{o} = 0\,\frac{m}{s}, then:

a = \frac{v}{t'}

max2010maxim [7]2 years ago
3 0

Answer:

a = (v-v0)      

     ____      where v = final velocity, v0

         t

Explanation:

Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,

= -9.3 m/s2.

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. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
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Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

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k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

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b) To get the unloaded length 1:  

l=x1-(F_1/k)

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2 years ago
Describe how electromagnetic radiation can ionise an atom. 2 marks
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