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Ainat [17]
2 years ago
9

A 1.0 mole pure sample of molten tin is dissolved in a 5.0 mole pure sample of molten copper. The solution is set aside to cool

and solidify. The atomic radius of tin is 140 pm and the atomic radius of copper is 128 pm. a. Identify the type of alloy that is formed. Justify your answer. b. Identify the solvent in this solution. Justify your answer. ​
Chemistry
1 answer:
Gala2k [10]2 years ago
3 0

Answer:

a. Bronze

b. Copper

Explanation:

a. The alloy formed <u>from the mixture of molten tin and molten copper, with copper having the over triple of the quantity of tin</u>, is bronze. Although, these two metals are often not the only metals present in bronze.

b. The solvent in this mixture is molten copper. This is because, <u>it has the larger percentage of the constituents</u> and hence can easily allow other constituents to be dissolved in it.

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Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
GenaCL600 [577]

Answer:

CN^- is a strong field ligand

Explanation:

The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).

Ligands that cause a large crystal field splitting such as CN^- are called strong field ligands. They lead to the formation of diamagnetic species. Strong field ligands occur towards the end of the spectrochemical series of ligands.

Hence the complex, Fe(CN)6 4− is diamagnetic because the cyanide ion is a strong field ligand that causes the six d-electrons present to pair up in a low spin arrangement.

5 0
2 years ago
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2
LekaFEV [45]
Molar mass CaCl₂ = 111.0 g/mol

number of moles:

n = mass of solute / molar mass

n = 85.3 / 111.0

n = 0.7684 moles of CaCl₂

M = n / V

0.788 M = <span>0.7684 / V
</span>
V = 0.7684 / 0.788

V = 0.97512 L

hope this helps!


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