Answer:
50 g of S are needed
Explanation:
To star this, we begin from the reaction:
S(s) + O₂ (g) → SO₂ (g)
If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.
According to stoichiometry, we can determine the moles of sulfur dioxide produced.
100 g. 1mol / 64.06g = 1.56 moles
This 1.56 moles were orginated by the same amount of S, according to stoichiometry.
Let's convert the moles to mass
1.56 mol . 32.06g / mol = 50 g
Answer:
C
green traveled les distance but still ended up in the same location as red
Answer:
Well this is a metathesis or partner exchange reaction....and barium sulfate is as soluble as a brick...
Explanation:
And so...
Ba(NO3)2(aq)+K2SO4(aq)→2KNO3(aq)+BaSO4(s)⏐↓
Note that you simply HAVE TO KNOW that barium sulfate is insoluble....as is lead sulfate, and as is (less so) calcium sulfate
Explanation:
<h2>5060 have three significant figures : Explanation given below </h2>
Explanation:
Significant figures
The significant figures (also known as the significant digits and decimal places) of a number are digits that possess certain meaning .
It includes all digits except: zeros
Rules to find significant figures
1.All non-zero digits are considered significant. For example, 23 has two significant figures.
2.Zeros in between two non-zero digits are significant: like in 202.1201 has seven significant figures.
3.Zeros to the left of the significant figures are not significant. For example, .000021 has two significant figures, zeros have no value .
4.Zeros to the right of the significant figures are significant.
That is the reason in number 5060 , it has 3 significant figures .
Answer:
Ketone
Explanation:
As you are stating here, we have a carbonated chain of three carbons, and the first and last has 3 Hydrogens, then this means that we have CH₃ . The center carbon is a carbon double bonded to oxygen.
In general terms this belongs to the carbonyl group. However, this alone does not represent a functional group, but when it's in a chain with other radycals or chains, it becomes a functional group.
In this case, the molecule you are talking here is the following:
CH₃ - CO - CH₃
This molecule is known as the Acetone, and has the general form of:
R - CO - R'
Which belongs to a ketone as a functional group.