Answer is: <span>unbalanced electronegativity of the hydrogens and oxygens as they share electrons.
Oxygen has greater electronegativity than hydrogen, because of that oxygen is partially negative and hydrogen is partially positive.
</span>Electronegativity<span> is a </span>chemical property<span> that describes the tendency of an </span>atom<span> to attract a shared pair of </span>electrons<span> towards itself.</span>
Answer:
The following subsections explain the explanation according to the particular circumstance.
Explanation:
- The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.
- The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.
Answer:
Volume of container = 0.0012 m³ or 1.2 L or 1200 ml
Explanation:
Volume of butane = 5.0 ml
density = 0.60 g/ml
Room temperature (T) = 293.15 K
Normal pressure (P) = 1 atm = 101,325 pa
Ideal gas constant (R) = 8.3145 J/mole.K)
volume of container V = ?
Solution
To find out the volume of container we use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First we find out number of moles
<em>As Mass = density × volume</em>
mass of butane = 0.60 g/ml ×5.0 ml
mass of butane = 3 g
now find out number of moles (n)
n = mass / molar mass
n = 3 g / 58.12 g/mol
n = 0.05 mol
Now put all values in ideal gas equation
<em>PV = nRt</em>
<em>V = nRT/P</em>
V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa
V = 121.87 ÷ 101,325 pa
V = 0.0012 m³ OR 1.2 L OR 1200 ml
Answer:
Th answer to your question is:
a) 3.5 x10⁻¹⁰ meters; 0.35 nm
b) 6857142.86 atoms
c) Volume = 2.06 x 10⁻²³ cm³
Explanation:
a) data
Uranium atoms = 3.5A°
meters
1 A° ---------------- 1 x 10 ⁻¹⁰ m
3.5A° --------------- x
x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters
1 A° ------------------ 0.1 nm
3.5 A° ---------------- 0.35 nm
b) 2.4 mm
Divide 2,40 mm / uranium diameter
But, first convert 3,5A° to mm = 3.5 x 10⁻⁷ mm
# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86
c) volume in cubic cm
Convert 3.5A° to cm = 3.5 x 10⁻⁸
Volume = 4/3 πr³ = (4/3) (3.14)(1.7 x10⁻⁸)³
Volume = 2.06 x 10⁻²³ cm³
beryllium & calcium are the two in the same column or family