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Novosadov [1.4K]
2 years ago
13

Based on the results of your titration, what volume of the sample would an adult need to consume to reach the recommended daily

amount? 60 mg is the recommened daily amount of vitamin C.
Ascorbic acid Volume of DCPIP in Total Volume of DCPIP

concentration (g/L) final syringe (mL) used (mL)

0.00 2.18 mL 0.18 mL

0.50 3.1 mL 0.6 mL

1.00 4.6 mL 2.2 mL

1.50 5.56 mL 3.39 mL

2.00 6.37 mL 4.37 mL

Unknown Trial 1 3.21 mL 1.21 mL

Unknown Trial 2 3.11 mL 1.11 mL

Unknown Trial 3 3.15 mL 1.06 mL

Chemistry
1 answer:
Mekhanik [1.2K]2 years ago
5 0

Answer:  85.7 mL

Explanation:

Given the information from the question as plotted in the graph i will be uploading along side this answer,

Average of total volume of DCPIP used is

= (1.21 + 1.11 + 1.06)mL / 3

= 1.12 mL

and corresponding ( ascorbic acid ) is 0.70 g/L

Two parameter given as volume of DCPIP in final syringe and total volume of DCPIP are quite ambiguous

700mg ⇒ 1 L

THEREFORE volume that contains 60mg =  (1000/700) × 60 = 85.7 mL

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Design a synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons or fewer.
Studentka2010 [4]

Answer:

Enolate Alkylation

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Explanation:

Design is illustrated in the attached document

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2 years ago
What elements are in NaC2HO4 and how many atoms are in each element​
JulijaS [17]

Answer:

Each molecule contains one atom of A and one atom of B. The reaction does not use all of the atoms to form compounds.

                 A + B ⟶ Product

Particles: 6      8              6

If six A atoms form six product molecules, each molecule can contain only one A atom.

The formula of the product is ABₙ.

If n = 1, we need six atoms of B.

If n = 2, we need 12 atoms of B. However, we have only eight atoms of B, so the formula of the product must be AB.

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Explanation:

Credit goes to @znk

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Equation: 3Cu(s) 8HNO3(aq) --> 2NO(g) 3Cu(NO3)2(aq) 4H2O(l) In the above reaction, the element oxidized is ______, the reduci
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Answer:

1. Cu

2. Cu

3. 2 electrons.

Explanation:

Step 1:

The equation for the reaction is given below:

3Cu(s) + 8HNO3(aq) -> 2NO(g) 3Cu(NO3)2(aq) + 4H2O(l)

Step 2:

Determination of the change of oxidation number of each element present.

For Cu:

Cu = 0 (ground state)

Cu(NO3)2 = 0

Cu + 2( N + 3O) = 0

Cu + 2(5 + (3 x -2)) =0

Cu + 2 (5 - 6) = 0

Cu + 2(-1) = 0

Cu - 2 = 0

Cu = 2

The oxidation number of Cu changed from 0 to +2

For N:

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N = 6 - 1

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NO = 0

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The oxidation number of N changed from +5 to +2

The oxidation number of oxygen and hydrogen remains the same.

Note:

1. The oxidation number of Hydrogen is always +1 except in hydride where it is - 1

2. The oxidation number of oxygen is always - 2 except in peroxide where it is - 1

Step 3:

Answers to the questions given above

From the above illustration,

1. Cu is oxidize because its oxidation number increased from 0 to +2 as it loses electron.

2. Cu is the reducing agent because it reduces the oxidation number of N from +5 to +2.

3. The reducing agent i.e Cu transferred 2 electrons to the oxidising agent HNO3 because its oxidation number increase from 0 to +2 as it loses its electrons. This means that Cu transfer 2 electrons.

7 0
2 years ago
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