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mart [117]
2 years ago
9

Draw two five carbon rings that share an atom.

Chemistry
1 answer:
Katena32 [7]2 years ago
8 0
Here’s the steps to do this & then a photo! Hope this helps!


Draw your electron rings. The circle with the "C" is a representative nucleus, so now you'll need to indicate the electron orbitals. The number of rings you need is to tied to the number of electrons you have. Carbon has 6 electrons. Since each ring has a maximum number of electrons that can be pictured, you'll have to do some math. The first ring can have a maximum of 2 electrons, the second ring a maximum of 8, the third ring a maximum of 18, etc. Carbon has 6 electrons, so you'll need to draw two concentric rings.
Draw your electrons. You can do this a couple different ways. Some people just draw circles on the rings and fill them in. In this case, you would draw 2 on the first ring and 5 on the second ring. The best way to draw electrons is to draw them as circles with minus signs inside. This indicates not only that they are electrons, but helps remind the viewer that electrons contain a negative charge.

You might be interested in
A sample that weighs 103.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the samp
aalyn [17]
1) we calculate the molar mass of He (helium) and Kr (Krypton).
atomic mass (He)=4 u
atomic mas (Kr)=83.8 u

Therefore the molar mass will be:
molar mass(He)=4 g/mol
molar mass(Kr)=83.8 g/mol.

1) We can find  the next equation:
mass=molar mass  x number of moles.

x=number of moles of helium
y=number of moles of helium. 

(4 g/mol) x  +(83.8 g/mol)y=103.75 g
Therefore, we have the next equation:

(1)

4x+83.8y=103.75


2) We can find other equation:

We have 30% helium atoms and 70% Kryptum atoms, therefore we have 30% Helium moles and 70% of Krypton moles.

1 mol  is always 6.022 * 10²³ atoms or molecules, (in this case atoms).

Then:
x=number of moles of helium
y=number of moles of helium.
(x+y)=number of moles of our sample.

x=30% of (x+y)

Therefore, we have this other equation:
(2)

x=0.3(x+y)


With the equations(1) and (2), we have the next system of equations:

4x+83.8y=103.75

x=0.3(x+y)  ⇒ x=0.3x+0.3y  ⇒    x-0.3x=0.3y  ⇒ 0.7 x=0.3y ⇒ x=0.3y/0.7
⇒x=3y/7

We solve this system of equations by substitution method.
x=3y/7

4(3y/7)+83.8y=103.75
lower common multiple)7
12y+586.6y=726.25
598.6y=726.25
y=1.21

x=3y/7=3(1.21)/7=0.52

We have 0.52 moles of  helium and 1.21 moles of Krypton.

1 mol=6.022 * 10²³ atoms

Total number of particles=(6.022 *10²³ atoms /1 mol) (number of moles of He+ number of moles of Kr).

Total number of particles=6.022 * 10²³ (0.52+1.21)=6.022 * 10²³ (1.73)=
=1.044 * 10²⁴ atoms.

Answer: The sample have 1.044 * 10²⁴ atoms.
6 0
2 years ago
Read 2 more answers
The active ingredient in Milk of Magnesia™ is Mg(OH)2. Magnesium hydroxide is insoluble in water, so the product is a mixture of
Liula [17]

Answer:  This chemical reaction is a neutralization reaction between the Milk of Magnesia and the HCl from the stomach. The balanced equation is Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)

Explanation:

The reaction between the HCl and the  Mg(OH)2 is a neutralizacion reaction ,  because the HCl is a strong acid and the  Mg(OH)2 is a weak base, then both react and the pH of the medium will increase, so the stomach trouble will dissapear.

Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)

Magnesium hydroxide is a weak base due to its very limited solubility in water. This property is a great advantage when treating the excess of HCl in the stomach, because the Mg(OH)2 molecule does not dissociated  easily until it reacts with the  hydrogen ion, H+ of the HCl. So the effect of the  Mg(OH)2 will last longer until the annoyance dissapear.

8 0
2 years ago
b) If 35 grams of copper (II) chloride react with 20 grams of sodium nitrate, how much sodium chloride can be formed? what is th
charle [14.2K]

Answer:

CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant, 13.7g of NaCl can be formed.

Explanation:

Based on the reaction:

CuCl₂ + 2NaNO₃ → 2NaCl + Cu(NO₃)₂

To solve the problem we must convert the mass of each reactant in order to find limiting reactant as follows:

<em>Moles CuCl₂ -Molar mass: 134.45g/mol-:</em>

35g * (1mol / 134.45g) = 0.26 moles

<em>Moles NaNO₃ -Molar mass: 84.99g/mol-:</em>

20g * (1mol / 84.99g) = 0.235 moles

For a complete reaction of 0.235 moles of NaNO₃ there are required:

0.235 moles NaNO₃ * (1 mol CuCl₂ / 2 mol NaNO₃) = 0.118 moles CuCl₂

As there are 0.26 moles CuCl₂,

<h3>CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant</h3><h3 />

As 2 moles of NaNO₃ produce 2 moles of NaCl, he moles of NaCl produced are: 0.235 moles NaCl. The mass is:

<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>

0.235 moles NaCl * (58.44g / mol) =

<h3>13.7g of NaCl can be formed</h3>
7 0
2 years ago
Write an equation that represents the action in water of rubidium hydroxide as an Arrhenius base.
Anika [276]

Answer:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

Explanation:

Arrhenius theory states that a compound is considered a base, if the compound can generate OH⁻ ions in aqueous solution.

Our compound is the RbOH.

When it is put in water, i can dissociate like this:

RbOH  → Rb⁺ +  OH⁻

As the hydroxide can gives the OH⁻ in water, it is considered as an Arrhenius's base

3 0
2 years ago
A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs
Mars2501 [29]
The answer is (4) Add enough solvent to 30.0 g of solute to make 1.0 L solution. The molarity is calculated using volume of the solution. When solute dissolving, the total volume will change. So the final volume of solution need to be 1.0 L.
4 0
2 years ago
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