Gravitational potential energy is observed when an object is not in rest or is in motion. In this case, the helicopter is in motion where the direction is going upward with a negative potential energy. Thank you for your question. Please don't hesitate to ask in Brainly your queries.
The simplest formula is C₅H₁₀O.
We must calculate the masses of C, H, and O from the masses given.
<em>Mass of C</em> =5.63 g CO₂ × (12.01 g C/44.01 g CO₂) = 1.536 g C
<em>Mass of H</em> = 2.30 g H₂O × (2.016 g H/18.02 g H₂O) = 0.2573 g H
<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H
= (2.20 – 1.536 – 0.2573) g = 0.406 g
Now, we must convert these masses to moles and find their ratios.
From here on, I like to summarize the calculations in a table.
<u>Element Mass/g Moles Ratio Integers </u>
C 1.536 0.1279 5.038 5
H 0.2573 0.2553 10.05 10
O 0.406 0.0254 1 1
The empirical formula is C₅H₁₀O.
Explanation:
The given reaction equation will be as follows.

Now, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
Therefore, this equation is balanced since atoms on both reactant and product sides are equal.
Thus, we can conclude that there is one sulfur atom in the products.
First, we assume that helium behaves as an ideal gas such that the ideal gas law is applicable.
PV = nRT
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. From the equation, if n, R, and T are constant, there is an inverse relationship between P and V. From the given choices, the container with the greatest pressure would be the 50 mL.
The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:

Converting moles of boric acid to mass:

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.