March: 240 * 0.4 = 96 used
240 - 96 = 144 remains in the tank
April : 144 * 0.25 = 36 used
144 - 36 = 108 remains in tank
answer: 108 gallons left at the end of April
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
b. (45 -t)/t
Step-by-step explanation:
c = remaining/drained
c = (60 -4/3t)/(4/3t) . . . . fill in values from problem statement
c = (45 -t)/t
