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2 years ago

What is the displacement of the iguana between 0s and 5s?

Physics

2 answers:

butalik [34]2 years ago

5 0

Answer:

18 meters

Explanation:

The displacement is the area under the graph.

The equation of the line from x=0 to x=3 is y = 8/3 x − 2. The x-intercept is (3/4, 0).

The area of the negative triangle is:

½ (3/4) (-2) = -0.75

The area of the positive trapezoid is:

½ ((5 − 3) + (5 − 3/4)) (6) = 18.75

The total area is 18.75 + -0.75 = 18.

Vinil7 [7]2 years ago

5 0

Answer: the displacement is 8m and the distance traveled is also 8 meters

Explanation:

It travels from -2 to 6, a difference of positive 8, and since that was its initial starting point, displacement is 8m, distance traveled also happens to be 8m

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Identify the false statement: Select one:

svet-max [94.6K]

Answer:

D) Synthesizers have always had a well-established presence in standard ensembles

Explanation:

As synthesizers are electronic music instruments that can create the sounds of many different musical instruments, they have been seen as a threat to many musicians since their invention.

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2 years ago

Read 2 more answers

The speed of sound in air is 320 ms-1 and in water it is 1600 ms-1. It takes 2.5 s for sound to reach a certain distance from th

Nonamiya [84]

Answer:

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

Explanation:

Given:

Speed of sound in air = 320 m/s

Speed of sound in water = 1600 m/s

Time taken to reach certain distance in air = 2.5 sec

We have to find the distance traveled by sound in air.

Distance = Product of speed and time.

⇒ $Distance = Speed\times time\ taken$

⇒ $Distance = 320\times 2.5$

⇒ $Distance = 800$ meters.

Now we have to find how much time the sound will take to travel in water.

⇒ Time = Ratio of distance and speed

⇒ $Time =\frac{distance}{speed}$

⇒ $Time =\frac{800}{1600}$ ...distance = 800 m and speed = 1600 m/s

⇒ $Time =\frac{1}{2}$

⇒ $Time =0.5$ seconds.

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

7 0

2 years ago

A man holding 7N weight moves 7m horizontal and 5m vertical , find the work done

SashulF [63]

Answer:

35 J

Explanation:

The man is holding the box: this means that he is applying a force vertically upward, to balance the weight of the box (which pushes downward).

Therefore, we can ignore the horizontal displacement of the man, because the force applied (vertically upward) is perpendicular to that displacement (horizontal), so the work done for that is zero.

So, only the vertical motion contributes to the work. The work done by the man is equal to the gain in gravitational potential energy of the box, so:

$W=(mg)\Delta h$

where

$mg=7 N$ is the weight of the box

$\Delta h=5 m$ is the vertical displacement

Substituting, we find

$W=(7N)(5 m)=35 J$

8 0

2 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th

qaws [65]

Answer:

The distance between both cars is 990 m

Explanation:

The equations for the position and the velocity of an object moving in a straight line are as follows:

x = x0 + v0 * t + 1/2 * a * t²

v = v0 + a * t

where:

x = position of the car at time "t"

x0 = initial position

v0 = initial speed

t = time

a = acceleration

v = velocity

First let´s find how much time it takes the driver to come to stop (v = 0). We will consider the origin of the reference system as the point at which the driver realizes she must stop. Then x0 = 0

With the equation of velocity, we can obtain the acceleration and replace it in the equation of position, knowing that the position will be 250 m at that time.

v = v0 + a*t

v-v0 / t = a

0 m/s - 71.0 m/s / t =a

-71.0 m/s / t = a

Replacing in the equation for position:

x = v0* t +1/2 * a * t²

250 m = 71.0 m/s * t + 1/2 *(-71.0 m/s / t) * t²

250 m = 71.0 m/s * t - 1/2 * 71.0 m/s * t

250m = 1/2 * 71.0m/s *t

t = 2 * 250 m / 71.0 m/s = 7.04 s

It takes the driver 7.04 s to stop.

Then, we can calculate how much time it took the driver to reach her previous speed. The procedure is the same as before:

v = v0 + a*t

v-v0 / t = a now v0 = 0 and v = 71.0 m/s

(71.0 m/s - 0 m/s) / t = a

71.0 m/s / t =a

Replacing in the position equation:

x = v0* t +1/2 * a * t²

390 m = 0 m/s * t + 1/2 * 71.0 m/s / t * t² (In this case, the initial position is in the pit, then x0 = 0 because it took 390 m from the pit to reach the initial speed).

390m * 2 / 71.0 m/s = t

t = 11.0 s

In total, it took the driver 11.0s + 5.00 s + 7.04 s = 23.0 s to stop and to reach the initial speed again.

In that time, the Mercedes traveled the following distance:

x = v * t = 71.0 m/s * 23.0 s = 1.63 x 10³ m

The Thunderbird traveled in that time 390 m + 250 m = 640 m.

The distance between the two will be then:

distance between both cars = 1.63 x 10³ m - 640 m = 990 m.

3 0

2 years ago

Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl

kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

7 0

2 years ago