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prohojiy [21]
2 years ago
9

What is the displacement of the iguana between 0s and 5s?

Physics
2 answers:
butalik [34]2 years ago
5 0

Answer:

18 meters

Explanation:

The displacement is the area under the graph.

The equation of the line from x=0 to x=3 is y = 8/3 x − 2.  The x-intercept is (3/4, 0).

The area of the negative triangle is:

½ (3/4) (-2) = -0.75

The area of the positive trapezoid is:

½ ((5 − 3) + (5 − 3/4)) (6) = 18.75

The total area is 18.75 + -0.75 = 18.

Vinil7 [7]2 years ago
5 0

Answer: the displacement is 8m and the distance traveled is also 8 meters

Explanation:

It travels from -2 to 6, a difference of positive 8, and since that was its initial starting point, displacement is 8m, distance traveled also happens to be 8m

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