If the Spirit of Australia, a boat,reaches speeds of 318.67 mph for 0.75 hours (45 minutes), what is the distance it traveled?

Physics

1 answer:

Rudiy272 years ago

6 0

Answer: 239.0025 miles.

Explanation:

First we have the relationship:

Distance = speed*time.

Because how it is worded, i guess that the boat can mantain a constant speed of 318.67 mph for 0.75 hours.

Then, we have the speed and the time, with those values we can find the distance.

speed = 318.67 mph

Time = 0.75 hours.

Distance = 318.67 mph*0.75h = 239.0025 miles.

You might be interested in

A photon has an energy of 5.53 × 10–17 j. what is its frequency in s–1 (h = 6.63 × 10–34 j • s)?

-BARSIC- [3]

Given: Energy E = 5.53 X 10⁻¹⁷ J; Velocity of light c = 2.998 x 10⁸ m/s

Planck's constant h = 6.63 x 10⁻³⁴ J.s

Required: Frequency f = ?

Formula: E = hc/λ and Frequency f = V/λ

λ = (6.63 x 10⁻³⁴ J.s)(2.998 X 10⁸ m/s)/(5.53 x 10⁻¹⁷ J)

λ = 3.59 X 10⁻⁹ m

For Frequency f = ?

f = c/λ

f = 2.998 x 10⁸ m/s/3.59 x 10⁻⁹m

f = 8.35 x 10¹⁶ Hz

6 0

2 years ago

Read 2 more answers

cicadas produce a sound that has a frequency of 123 Hz. what is the wavelength of this sound in the air? the speed of sound in a

mojhsa [17]

Answer: 2.72 metres

Explanation:

Given that:

frequency of sound F = 123 Hz. wavelength of sound in the air = ?

speed of sound in air V = 334 m/s

Recall that wavelength is the distance covered by the wave after one complete cycle. It is measured in metres, and represented by the symbol λ.

So, apply V = F λ

λ = V /F

λ = 334m/s / 123Hz

λ = 2.72m

Thus, the wavelength of this sound in the air is 2.72 metres

4 0

2 years ago

A two-resistor voltage divider employing a 2-k? and a 3-k? resistor is connected to a 5-V ground-referenced power supply to prov

vesna_86 [32]

Answer:

circuit sketched in first attached image.

Second attached image is for calculating the equivalent output resistance

Explanation:

For calculating the output voltage with regarding the first image.

$Vout = Vin \frac{R_{2}}{R_{2}+R_{1}}$

$Vout = 5 \frac{2000}{5000}[/[tex][tex]Vout = 5 \frac{2000}{5000}\\Vout = 5 \frac{2}{5} = 2 V$

For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.

so.

$R_{out} = R_{2} || R_{1}\\R_{out} = 2000||3000 = \frac{2000*3000}{2000+3000} = 1200$

Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.

if the -5% is applied to both resistors the Voltage is still 5V because the quotient has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:

$Vout = 5 \frac{1900}{4900}\\Vout = 5 \frac{19}{49} = 1.93 V$