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babunello [35]
2 years ago
11

Q3. Why do you think there were so many heated debates about cell theory? Click or tap here to enter text.​

Chemistry
1 answer:
Korolek [52]2 years ago
8 0
Why were there so many heated debates around the development of the cell theory? There were no concrete information about the development of the cell, thus they did not have the evidence to come to conclusions. People would argue about what theory was correct. who named the cell?
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When a complex ion forms, ______________ arrange themselves around _________, creating a new ion with a charge equal to the sum
alisha [4.7K]

Answer:

lignands, the central atom/metal ion

Explanation:

7 0
2 years ago
Why does silver iodide have a higher melting point than vanillin
MAVERICK [17]
AgI has a higher melting point than vanillin because it is an ionic compound. The bonds are held more tightly together than in vanillin because it is a covalent compound. Ionic bonds have a higher melting point because the electrons are being transferred from one atom to the other.
5 0
2 years ago
Draw all of the constitutional isomers of the molecule with formula C3H5Br. Ignore geometric and stereoisomers.
Kay [80]

Answer:

-) 3-bromoprop-1-ene

-) 2-bromoprop-1-ene

-) 1-bromoprop-1-ene

-) bromocyclopropane

Explanation:

In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):

I.D.H~=~\frac{(2C)+2+(N)-(H)-(X)}{2}

In the formula we have 3 carbons, 5 hydrogens, and 1 Br, so:

I.D.H~=~\frac{(2*3)+2+(0)-(5)-(1)}{2}~=~1

We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.

We can start with a linear structure with 3 carbon with a double bond in the first carbon and the Br atom also in the first carbon (<u>1-bromoprop-1-ene</u>). In the second structure, we can move the Br atom to the second carbon (<u>2-bromoprop-1-ene</u>), in the third structure we can move the Br to carbon 3 (<u>3-bromoprop-1-ene</u>). Finally, we can have a cyclic structure with a Br atom (<u>bromocyclopropane</u>).

See figure 1

I hope it helps!

7 0
2 years ago
when the volume of a gas is changed from 3.75 L to 6.52 L the temperature will change from 100k to _K
harkovskaia [24]

The temperature will change from 100K to 173.87 K

calculation

by use of    law  that is V1/T1=V2/T2

V1=3.75 L

T1=100k

V2=6.53 L

T2=?

make T2 the subject of the formula

T2=(V2 xT1)V1

=6.52 x100/3.75=173.87K


4 0
2 years ago
Read 2 more answers
When a sample of oxygen gas in a closed container of constant volume is heated until its absolute temperature is doubled, which
saul85 [17]

Answer: b. pressure

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas  = p

P_2 = final pressure of gas  = ?

T_1 = initial temperature of gas  = t

T_2 = final temperature of gas = 2t

\frac{p}{t}=\frac{P_2}{2t}

P_2=2p

Thus the pressure also doubles when absolute temperature is doubled.

7 0
2 years ago
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