The man ran <u>4252.5 meters.</u>
Why?
To solve the problem, we need to divide the exercise into two movements, the first on while the was running at 4.5 m/s for 15 min, and then, while he was slowing down (going up because of the hill).
First movement: Running at 4.5 m/s for 15 min.
We need convert from minutes to seconds,
Now, calculating the distance covered for the first movement, we have:
So, we know that the man covered 4050m for the first movement, it will be our initial position for the second movement.
Second movement: acceleration -0.05m/s^2 (because he's slowing down) for 90 seconds, at 4.5m/s.
Hence, we have that he ran 4252.5 m.
Have a nice day!
In atmospheric science, surface pressure<span> is the atmospheric </span>pressure<span> at a location on Earth's </span>surface<span>. It is directly proportional to the mass of air over that location. For numerical reasons, atmospheric models such as general circulation models (GCMs) usually predict the nondimensional logarithm of </span>surface pressure<span>.
The answer is decrease more slowly
</span>
Explanation:
It is given that,
Speed of the jet airplane with respect to air, 
If the wind at the airliner’s cruise altitude is blowing at 100 km/h from west to east, 
(A) Let 
is the speed of the airliner relative to the ground if the airplane is flying from west to east,
(B) Let 
is the speed of the airliner relative to the ground if the airplane is flying from east to west,
Hence, this is the required solution.
Answer:1.301 s
Explanation:
Given
Initial Velocity(u)=30 m/s
Height of cliff=8.3 m
Time taken to cover 8.3 m
here Initial vertical velocity is 0
Horizontal distance
In order to answer this question ... strange as it may seem ...
we only need one of those measurements that you gave us
that describe the door.
The door is hanging on frictionless hinges, and there's a torque
being applied to it that's trying to close it. All we need to do is apply
an equal torque in the opposite direction, and the door doesn't move.
Obviously, in order for our force to have the most effect, we want
to hold the door at the outer edge, farthest from the hinges. That
distance from the hinges is the width of the door ... 0.89 m.
We need to come up with 4.9 N-m of torque,
applied against the mechanical door-closer.
Torque is (force) x (distance from the hinge).
4.9 N-m = (force) x (0.89 m)
Divide each side by 0.89m: Force = (4.9 N-m) / (0.89 m)
= 5.506 N .
