Answer:
1.6 L is the volume of NaOH that has reacted
Explanation:
The balanced reaction is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
This is a neutralization reaction between a strong acid and a strong base. The products are the correspond salt and water.
We propose this rule of three:
1 mol of sulfuric acid needs 2 mol of NaOH to react to react
Then, 2.4 moles of H₂SO₄ will react with (2.4 . 2) / 1 = 4.8 moles of NaOH
As molarity is 3M, we can determine the volume of our solution
Molarity (M) = mol / volume(L) → Volume(L) = mol / Molarity
Volume(L) = 4.8 mol / 3 M = 1.6 L
Answer:
Si14- Si^4+
As33- As^3-
Mg12- Mg^2+
Rb37- Rb^+
F9- F^-
Ge32- Ge^4+
Sn50- Sn^2+, Sn^4+
Explanation:
The elements shown in the answer have their common ions written beside them.
Silicon mostly forms positive ions in oxyacids and complex ions. Arsenic mostly forms its anion. Magnesium forms only the +2cation just as rubidium only forms the +1 cation. The fluoride ion is F^- while tin may for a +2*or +4 cation. Germanium usually forms the +4 cation.
Answer: the answer is option (D). k[P]²[Q]
Explanation:
first of all, let us consider the reaction from the question;
2P + Q → 2R + S
and the reaction mechanism for the above reaction given thus,
P + P ⇄ T (fast)
Q + T → R + U (slow)
U → R + S (fast)
we would be applying the Rate law to determine the mechanism.
The mechanism above is a three step process where the slowest step seen is the rate determining step. From this, we can see that this slow step involves an intermediate T as reactant and is expressed in terms of a starting substance P.
It is important to understand that laws based on experiment do not allow for intermediate concentration.
The mechanism steps for the reactions in the question are given below when we add them by cancelling the intermediates on the opposite side of the equations then we get the overall reaction equation.
adding this steps gives a final overall reaction reaction.
2P + Q ------------˃ 2R + S
Thus the rate equation is given as
Rate (R) = K[P]²[Q]
cheers, i hope this helps
Answer:
The adjustable legs and the table of sand.
<em>Note:The question is incomplete. The complete question is given below.</em>
Using Models to Answer Questions About Systems
Armando’s class was looking at images of rivers formed by flowing water. Most of the rivers were wide and shallow, but one river was narrow and deep. Armando’s class thinks that this river is narrow and deep because:
- the hill that the water flowed down was very steep, or
- the sand grains that the water flowed through were very small.
Armando designed the model below to try to answer the question: Why is this river so narrow and deep?
Explanation:
The model designed by Armando will be helpful to answer the question because of the following features it possesses:
1. An adjustable leg- since one of the hypotheses put forward by the class to explain why the river was narrow and deep was that the hill that the water flowed down was very steep, the adjustable legs can be lowered or raised in order to make the slope shallower or steeper so that their hypothesis can be tested.
2. A table of sand- the table of sand serves as the streambed. By adjusting the size of the sand grains to be larger or smaller, the students will be able to to test their second hypothesis that the small size sand grains that the water flowed through was the reason for the river to be narrow and deep.
The results of their experiments will enable them to come to a conclusion.
Answer:
Heat lost to the surroundings
Heat lost to the thermometer
Explanation:
All changes in heat, or energy, can be explained. Many of the reactions or changes we see in the world involve the conversion of energy. For example as we heat up a substance (eg. water), the amount of energy we put in should give us an exact temperature. However, this is a "perfect world" scenario, and does not occur in real life. Whenever heat is added to a substance like water, we always need to account for the energy that is going to be lost. For example, heat lost to evaporation or even the effect of measuring the temperature with a thermometer (the introduction of anything including a thermometer will affect the temperature).
