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Anettt [7]
2 years ago
9

Match each tool on the left with its most likely use on the right by choosing the correct number. ruler scale telescope thermome

ter microscope 1. Measuring the weight of an apple 2. Studying a distant object 3. Studying a very small object 4. Measuring the length of a book 5. Measuring the temperature of a cup of tea
Chemistry
1 answer:
RideAnS [48]2 years ago
7 0

Answer:

1. Measuring the weight of an apple- scale.

2. Studying a distant object- telescope.

3. Studying a very small object- microscope.

4. Measuring the length of a book- ruler.

5. Measuring the temperature of a cup of tea- thermometer.

Explanation:

1. A scale or measuring scale is used to measure or take the weight of any object. It can be either an analog or digital scale as long as the measurements can be taken from it. So, <u>measuring the weight of an apple can be done on a measuring scale</u>.

2. A telescope is an instrument that is used in scientific, especially in space explorations, to study a distant object in the universe/ sky. It gives a clear image and enables a person to view things closer than they are. So, <u>a telescope can be used to study distant objects</u>.

3. <u>A microscope is used to study very different small objects</u>, such as microbes and other organisms. It enlarges the objects to be viewed and thus, enables them to be studied in detail.

4. <u>A ruler may be used to measure the length of a book</u>. It has indications or marks by which the lengths can be taken.

5. <u>A thermometer is an instrument that is used to measure the temperature of anything</u>, be it a person or even other things such as food and even a cup of tea.  

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A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc
GrogVix [38]

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em>(\frac {J}{Kg.K})</em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat (\frac {J}{Kg.K})</em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting  the given data in Equation

<em>Specific heat of Aluminium  = \frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})</em>

3 0
2 years ago
Read 2 more answers
How many moles of alanine, C3H7NO2, are there in 159 g of alanine?How many moles of alanine, C3H7NO2, are there in 159 g of alan
Vanyuwa [196]

To find the number of moles of Alanine, we first need to find its molar mass

<u>Finding the Molar mass:</u>

To our convenience, we are already given the chemical formula of Alanine

Chemical formula:  C₃H₇NO₂

Now, we will use this formula to find the molar mass of Alanine

to do that, we will replace the chemical symbols of elements with their respective molar masses and add them together

<em>We know the following molar masses:</em>

<em>C is 12 g/mol</em>

<em>H is 1 g/mol</em>

<em>N is 14 g/mol</em>

<em>O is 16 g/mol</em>

Now, we will replace the chemical symbols with their molar mass and will be multiplied by their values in subscript

C₃H₇NO₂

Molar mass = (12)*3  + (1)*7 + (14)*1 + (16)*2

Molar mass = 36 + 7 + 14 + 32

Molar mass = 89 grams/mol

<u>Number of moles of Alanine in a 159 gram sample:</u>

Number of moles = Given mass / Molar mass

Number of moles = 159 / 89

Number of Moles = 1.78 moles

5 0
2 years ago
A patient is receiving 3000 mL/day of a solution that con-
frutty [35]

Answer:

600 kCal/ day

Explanation:

You can solve this type of problems using proportions, with the rule of three.

Follow these steps:

1. Analyze the giving data

2. Organize it

3.Write the proportions  

4. Clear the value you are looking for

5. Solve the equations by multiplying or dividing

Now for the exercise:

You have the following data:

3000 mL Solution per 1 day ----> 3000 mL S

The concentration of the solution is  

5 g of dextrose per 100 mL  Solution ----> 5g D - 100 mL S

The glucose provides some specific energy

4 kCal per 1 g of dextrose ----> 4kCal - 1 g D

First find the total grams of  dextrose (glucose) given in one day.

3000 mL S - x g D?

 100 mL S - 5 g D

The grams of glucose given in one day

xg D? = 3000 mL S(5 g D)/100 mL S  

you also can cancel the units mL S

xg D? = 150 g D.

Answer: The grams given in one day of glucose are 150 g /day

Now find the total Energy in those grams:

4 kCal -      1 g D

x kCal?-150 g D

Clear x kCal?

x kCal? = 4kCal (150g D)/(1g D)

x kCal? = 600 kCal  remember is for one day!

so the answer is

The patient is receiving 600 kCal/day

5 0
2 years ago
If at 20 ∘C and a partial pressure of 760 mmHg, the solubility of CO2 in water is 0.169 g/100mL, what is the solubility of CO2 i
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In standardizing the 0.1 m naoh in three trial runs suppose the concentrations of naoh obtained are
Luba_88 [7]
Answer: 0.104M


Explanation:

1) The question is incomplete. This is the complete question:

In standardizing the 0.1M NaOH in three trial runs, suppose the concentrations of NaOH obtained are .108M, .102M, and .103M. Given this data, what concentration of NaOH should be used to calculate the moles of OH- used in the titration to analyze aspirin?

2) Since, 3 trials have bee run and each time it was obtained the concentration 3 different but similar concentrations for the NaOH solution, the best number to use is the average.

Precisely, there were run 3 trials to reduce the random errors of the measurements, and since all the 3 values make sense the best is to use the average of the three data.


3) Calculations:

Average = (0.108M + 0.102M + 0.103M) / 3 = 0.313M / 3 = 0.104M


4) It could also be considered that the number 0.108 is an outlier, but that can only be verified if you run more trials and so detect if 0.108M obeys to an  issue when the first trial was done. So, with more information you could tell whether you use 0.108M to calculate the average or should discard it.
5 0
2 years ago
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