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2 years ago

Why does frost bite occur in mountain climbers ?

Physics

2 answers:

san4es73 [151]2 years ago

7 0

Answer:

The higher the altitude the colder

Explanation:

Mountains are very high up obviously higher then the ground. It is colder so it makes it easier for mountain climbers to get frost bite because of the high altitude.

Hope this helps:)

Alenkinab [10]2 years ago

5 0

Answer:

Because they are in places that may be extremely cold

Explanation:

For example take Mount Everest. This place is a very high mountain, and is very cold. Usually hikers would get a frost bite from how cold it is in there. According to google, "Frostbite is an injury caused by freezing of the skin and underlying tissues."

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A cylinder rotating about its axis with a constant angular acceleration of 1.6 rad/s2 starts from rest at t = 0. At the instant

OverLord2011 [107]

Answer:

The magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

Explanation:

The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.

The radial acceleration is given by;

$a_t = ar$

where;

a is the angular acceleration and

r is the radius of the circular path

$a_t = ar\\\\a_t = 1.6 *0.13\\\\a_t = 0.208 \ m/s^2$

Determine time of the rotation;

$\theta = \frac{1}{2} at^2\\\\0.4 = \frac{1}{2} (1.6)t^2\\\\t^2 = 0.5\\\\t = \sqrt{0.5} \\\\t = 0.707 \ s\\\\$

Determine angular velocity

ω = at

ω = 1.6 x 0.707

ω = 1.131 rad/s

Now, determine the radial acceleration

$a_r = \omega ^2r\\\\a_r = 1.131^2 (0.13)\\\\a_r = 0.166 \ m/s^2$

The magnitude of total linear acceleration is given by;

$a = \sqrt{a_t^2 + a_r^2} \\\\a = \sqrt{0.208^2 + 0.166^2} \\\\a = 0.266 \ m/s^2\\\\a = 0.27 \ m/s^2$

Therefore, the magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

5 0

2 years ago

Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.91 J1.91 J of work to set the ball s

Black_prince [1.1K]

Answer:

ω = 4.07 rad/s

Explanation:

By conservation of the energy:

W = ΔK

$1.91J = I/2*\omega^2$

where $I = 2/3*m*R^2=0.23kg.m^2$

Solving for ω:

$\omega = \sqrt{W*2/I} =4.07rad/s$

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2 years ago

A stand shows a pendulum in 5 positions. A has the pendulum bob at a 45 degree angle to the left. C has the pendulum bob straigh

kotegsom [21]

Answer:

plz brainliest

Explanation:

position A : is all potential

position B : is losing potential and gaining kinetic energy

position c : is all kinetic

position D : is losing kinetic and gaining potential

position E : is all potential

thx have a great day

6 0

2 years ago

Read 2 more answers

A negatively charged object is located in a region of space where the electric field is uniform and points due north. the object

Blizzard [7]

- The largest increase in potential energy occurs when the charge is moving north. This is because the charge is negative, so it acquires potential energy when moving in the same direction of the field (viceversa, a positive charge when moving in the direction of the field it loses potential energy converting it into kinetic energy). The amount of potential energy gained is equal to the product of the charge and the distance covered:
$\Delta U = e d$

- The second largest increase is when the charge is moving east. In this case, actually, the variation of potential energy is zero. This is because the charge is moving perpendicular to the field, and so it is moving along points with same potential. Therefore, in this case the variation of potential energy is zero:
$\Delta U = 0$

- Finally, when the charge is moving south, it loses potential energy. This is because it is moving against the electric field, and since it is a negative charge, in this direction it loses potential energy converting it into kinetic energy. Therefore, in this case:
$\Delta U = - e d$

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2 years ago

A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he

igor_vitrenko [27]

Answer:

508 J/kg/C

Explanation:

Energy Lost by water = Energy gained by block

mcT = mcT [bolded is for water, italicised is for block]

(0.217)(4186)(25 - 16.4) = (0.350)(c)(16.4 + 27.5)

15.365c = 7811.9132

c = 508 J/kg/C (3 sf)

5 0

2 years ago

Why does frost bite occur in mountain climbers ?​

Why does frost bite occur in mountain climbers ?