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2 years ago

What is the coefficient of the term 12p in the expression 12p+9q

Mathematics

2 answers:

Tju [1.3M]2 years ago

8 0

Answer:

Step-by-step explanation:

disa [49]2 years ago

4 0

Answer:

The answer is 12,

Step-by-step explanation:

12 is the coefficient because it is the number multiplied by the variable p in the equation.

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The volume of a cube with side length x is V(x)=x^3. The volume of a cylinder with radius x and height 0.5x is shown in the grap

abruzzese [7]

Answer:

the cylinder volume is greater

Step-by-step explanation:

The volume of a cube with x=1 is ...

V(1) = 1^3 = 1

The graph shows y ≈ 1.5 for x=1. Since 1.5 > 1, the volume of the cylinder is greater.

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2 years ago

marco has a piece of wood that measures 9 x 1/10 6 x 1/100 4 x 1/1000 meter. how can this measurement be written as a decimal?

Darina [25.2K]

Based on the given values above, this is how the measurements can be written as a decimal.
Firstly, we need to convert the fractions into decimals first:
a. 1/10 is 0.1
b. 1/100 is 0.01
c. 1/1000 is 0.001
Next, we multiply this to their corresponding numbers given:
a. 9 x 0.1 is 0.9 meter
b. 6 x 0.01 is 0.06 meter
c. 4 x 0.001 is 0.004 meter
Therefore, the measurements of the piece of wood that Marco has are: 0.9, 0.06 and 0.004 meters. Hope this answer helps.

6 0

2 years ago

A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye

natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

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2 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$

d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

We have that $\gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0)$ so the acceleration is given by $\sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10$

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2 years ago

The data set represents the number of rings each person in a room is wearing.

MrRa [10]

If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.

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2 years ago

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What is the coefficient of the term 12p in the expression 12p+9q​

What is the coefficient of the term 12p in the expression 12p+9q