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earnstyle [38]
2 years ago
6

What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?

Chemistry
1 answer:
Nutka1998 [239]2 years ago
6 0

Answer:

1.2×10²³ atoms.

Explanation:

Data obtained from the question include:

Mole of propanone = 0.20 mole

Number of atoms of propanone =.?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of propanone also contains 6.022×10²³ atoms.

Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:

1 mole of propanone contains 6.022×10²³ atoms.

Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Thus, 0.20 mole of propanone contain

1.2×10²³ atoms.

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What is the melting point of tert-butanol? Besides using a heat lamp, what other options might there be for dispensing a given a
damaskus [11]

Answer:

For dispensing, weigh it out.

Yes, a different solvent such as ethanol could be used.

Explanation:

Besides using various methods for melting the <em>tert</em>-butanol in order to pour it out and measure a given volume, the <em>tert</em>-butanol could be weighed out in a beaker using a scale. Depending on the temperature of the laboratory, the <em>tert</em>-butanol could be a solid or a liquid/solid mixture.

In general, a different solvent such as ethanol could be used in place of <em>tert</em>-butanol as long as the solvent is a low molecular weight alcohol.

6 0
2 years ago
5. Hydrochloric Acid + Sodium Hydroxide à Sodium<br> Chloride +
erma4kov [3.2K]

HCl Acid + Sodium Hydroxide ----> Sodium  Chloride + water.

<u>Explanation</u>:

  • The reaction between an acid and a base is known as a neutralization reaction. The reaction of an acid with a base to give salt, water and heat is called neutralization.
  • When hydrochloric acid reacts with sodium hydroxide, sodium chloride and water are produced.  

                             HCl + NaOH → NaCl + H2O + Heat

  • The heat evolved in the neutralization reaction raises the temperature of the reaction mixture.    
  • An electro-electrodialysis process (EED) is utilized to create HCl and NaOH from exchange NaCl. NaOH and HCl arrangements with purity higher than 99.9% are acquired. The experimental estimations of the transitions for HCl and NaOH are contrasted and values determined from the incorporation of the Nernst–Planck electro dispersion conditions.
5 0
2 years ago
In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for
joja [24]

Answer:

ΔG° = -118x10³ J/mol

Explanation:

The two half-reactions in the cell are:

Oxidation half-reaction:

Co(s) → Co²⁺(aq) + 2e⁻; E° = -0,28V

Reduction half-reaction:

Cu²⁺(aq)+2e⁻ → Cu(s); E° = 0,34V

The E° of the cell is defined as:

E_{cell} = E_{red} - E_{ox}

Replacing:

0,34V - (-0,28V) = 0,62V

It is possible to obtain the keq from E°cell with Nernst equation thus:

nE°cell/0,0592 = log (keq)

Where:

E°cell is standard electrode potential (0.62 V)

n is number of electrons transferred (2 electrons, from the half-reactions)

Replacing:

0,62V×2/0,0592 = log (keq)

20,946 = log keq

keq = 8,83x10²⁰≈ 5,88x10²⁰

ΔG° is defined as:

ΔG° = -RT ln Keq

Where R is gas constant (8,314472 J/molK) and T is temperature (298K):

ΔG° = -8,314472 J/molK×298K ln5,88x10²⁰

<em>ΔG° = -118x10³ J/mol</em>

<em />

I hope it helps!

8 0
2 years ago
Which of the following statements best describes the Aufbau principle?
dsp73
The answer is the choice A
7 0
2 years ago
In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e
salantis [7]
<h2>Answer:</h2>

1.58  × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 =  1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water:  90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 .  1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58  × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.


4 0
2 years ago
Read 2 more answers
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