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2 years ago

Why watchman does no work but gets tired ?

1 answer:

8 0

Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.

Explanation:

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An amusement park ride spins you around in a circle of radius 2.5 m with a speed of 8.5 m/s. If your mass is 75 kg, what is the

zhannawk [14.2K]

B is the answer to this truly did the math

3 0

2 years ago

Read 2 more answers

Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment

Dominik [7]

Answer:

$\mu=0.74$

Explanation:

It is given that,

Speed of one quoll around a curve, v = 3.2 m/s (maximum speed)

Radius of the curve, r = 1.4 m

On the curve, the centripetal force is balanced by the frictional force such that the coefficient of frictional is given by :

$\mu=\dfrac{v^2}{rg}$

$\mu=\dfrac{(3.2\ m/s)^2}{1.4\ m\times 9.8\ m/s^2}$

$\mu=0.74$

So, the coefficient of static friction between the quoll's feet and the ground in this trial is 0.74. Hence, this is the required solution.

6 0

2 years ago

Read 2 more answers

Pions have a half-life of 1.8 x 10^-8 s. A pion beam leaves an accelerator at a speed of 0.8c. What is the expected distance ove

Nuetrik [128]

Answer:

the expected distance is 4.32 m

Explanation:

given data

half life time = 1.8 × $10^{-8}$ s

speed = 0.8 c = 0.8 × 3 × $10^{8}$

to find out

expected distance over

solution

we know c is speed of light in air is 3 × $10^{8}$ m/s

we calculate expected distance by given formula that is

expected distance = half life time × speed .........1

put here all these value

expected distance = half life time × speed

expected distance = 1.8 × $10^{-8}$ × 0.8 × 3 × $10^{8}$

expected distance = 4.32

so the expected distance is 4.32 m

5 0

2 years ago

A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 cans, 0.355 - l each,

Alona [7]

Flow rate = 220*0.355 l/m = 78.1 l/min = 1.3 l/s = 0.0013 m^3/s

Point 2:
A2= 8 cm^2 = 0.0008 m^2
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa

Point 1:
A1 = 2 cm^2 = 0.0002 m^2
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 = ?
Height = 1.35 m

Applying Bernoulli principle;
P2+1/2*V2^2/density = P1+1/2*V1^2/density +density*gravitational acceleration*height
=>152000+0.5*1.625^2*1000=P1+0.5*6.5^2*1000+1000*9.81*1.35
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31-34368.5 = 118951.81 Pa = 118.95 kPa

3 0

2 years ago

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A uniform magnetic field of 0.50 T is directed along the positive x axis. A proton moving with a speed of 60 km s enters this fi

tatuchka [14]

Explanation:

It is given that,

Magnetic field, B = 0.5 T

Speed of the proton, v = 60 km/s = 60000 m/s

The helical path followed by the proton shown has a pitch of 5.0 mm, p = 0.005 m

We need to find the angle between the magnetic field and the velocity of the proton. The pitch of the helix is the product of parallel component of velocity and time period. Mathematically, it is given by :

$p=v_{||}\times T$