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frosja888 [35]
1 year ago
10

8. A student drew the diagram below to show the movement of water through a hydroelectric dam. et att Hydroelectric Dam ET Water

Level 1 Powerhouse Dam Water Level 2 Transmisslon lines Cenerico LLE ESSETIS om Turbing Fus The student used the diagram to describe changes in the potential and kinetic energy of the water. At which location is the gravitational potential energy of the water the greatest?​
Chemistry
2 answers:
Advocard [28]1 year ago
4 0

Answer:

Answer W

Explanation:

olga_2 [115]1 year ago
3 0

Answer: location Y

Explanation:    

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The density of an unknown crystal is 2.65gmL. If a 4.46 g sample of the crystal is added to a graduated cylinder containing 25.0
jolli1 [7]

Answer:

Total volume after adding crystal = 26.7 mL

Explanation:

Given data:

Density of crystal = 2.65 g/mL

Mass of sample = 4.46 g

Volume of water = 25.0 mL

Volume after adding crystal = ?

Solution:

First of all we will calculate the volume of crystal.

d = m/v

2.65 g/mL = 4.46 g/ v

v = 4.46 g/2.65 g/mL

v = 1.7 mL

Total volume after adding crystal = Volume of water + Volume of metal

Total volume after adding crystal = 25.0 mL + 1.7 mL

Total volume after adding crystal = 26.7 mL

8 0
1 year ago
A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent
Degger [83]

Answer :  The % of (+) limonene isomer = 79%


                The % of (-) limonene isomer = 0%


                The % of enantiomeric excess = 58%


Explanation :   Enantiomeric excess (ee) is the measurement of purity used for chiral substances.


Given,


% of pure limonene enantiomer = The % of (+) limonene isomer = 79%


Therefore, The % of (-) limonene isomer = 0%


Formula used :  

\%(+)\text{ isomer}=\frac{ee}{2}+50\%


Where,         ee → enantiomeric excess


Now, put all the values in above formula, we get the value of enantiomeric excess (ee).


     {ee}=\frac{\%(+)-50\%}{2}


            =\frac{79\%-50\%}{2}


              = 58%



7 0
1 year ago
Read 2 more answers
The Mond process produces pure nickel metal via the thermal decomposition of nickel tetracarbonyl: Ni(CO)4 (l) → Ni (s) + 4CO (g
Yuki888 [10]

<u>Answer:</u> The volume of CO formed is 254.43 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of Ni(CO)_4 = 444 g

Molar mass of Ni(CO)_4 = 170.73 g/mol

Putting values in above equation, we get:

\text{Moles of }Ni(CO)_4=\frac{444g}{170.73g/mol}=2.60mol

For the given chemical reaction:

Ni(CO)_4(l)\rightarrow Ni(s)+4CO(g)

By stoichiometry of the reaction:

1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.

So, 2.60 moles of nickel tetracarbonyl will produce = \frac{4}{1}\times 2.60=10.4mol of carbon monoxide.

Now, to calculate the volume of the gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of the gas = 752 torr

V = Volume of the gas = ? L

n = Number of moles of gas = 10.4 mol

R = Gas constant = 62.364\text{ L Torr }mol^{-1}K^{-1}

T = Temperature of the gas = 22^oC=(273+22)K=295K

Putting values in above equation, we get:

752torr\times V=10.4mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 295K\\\\V=254.43L

Hence, the volume of CO formed is 254.43 L.

5 0
2 years ago
For the following equilibrium: A+2B⇋C+3D If the change in concentration for B is 0.44 M, what will be the change in concentratio
Readme [11.4K]

Answer:0.22M

Explanation:

5 0
1 year ago
Which of the following are elements, which are molecules but not compounds, which are compounds but not molecules, and which are
andreev551 [17]

Explanation:

Molecules of compounds are are compounds composed two or more than two different elements.

Molecules of an elements are made up two or more than two numbers of same type of atoms

(a) SO_2

It is compound composed of sulfur and oxygen element.

(b) S_8

It is a molecules of a single element made up of 8 sulfur atoms.

(c) Cs

It is a symbol of an element named cesium.

(d) N_2O_5

It is compound composed of nitrogen and oxygen element.

(e) O

It is a symbol of an element named oxygen.

(f) O_2

It is a molecule of a single element made up of 2 oxygen atoms.

(g) O_3

It is a molecule of a single element made up of 3 oxygen atoms.

(h)CH_4

It is compound composed of carbon and hydrogen element.

(i) KBr

It is compound composed of potassium and bromine element.

(j) S

It is a symbol of an element named sulfur.

(k) P_4

It is a molecule of a single element made up of 4 phosphorus atoms.

(l) LiF

It is compound composed of lithium and fluorine element.

4 0
1 year ago
Read 2 more answers
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