Answer:
83%
Explanation:
On the surface, the weight is:
W = GMm / R²
where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.
In orbit, the weight is:
w = GMm / (R+h)²
where h is the height of the shuttle above the surface of the Earth.
The ratio is:
w/W = R² / (R+h)²
w/W = (R / (R+h))²
Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:
w/W = (6.4×10⁶ / 7.03×10⁶)²
w/W = 0.83
The shuttle in orbit retains 83% of its weight on Earth.
v₀ = initial speed of the object = 8 meter/second
v = final speed of the object = 16 meter/second
t = time taken to increase the speed = 10 seconds
d = distance traveled by the object in the given time duration = ?
using the kinematics equation
d = (v + v₀) t/2
inserting the above values in the above equation
d = (16 + 8) (10)/2
d = 120 meter
<h2>The K.E of the charge is 1.02 x 10⁻¹⁷ J</h2>
Explanation:
When the charge of 2e is placed in between the plates .
The force applied on this charge by plates is = q E
here q is the magnitude of charge = 2 e = 2 x 1.6 x 10⁻¹⁹ C
and E is the magnitude of electric field intensity
The work done = Force x displacement
Thus W = q E x S
here S is displacement
Therefore W = 2 x 1.6 x 10⁻¹⁹ x 4 x 8
= 1.02 x 10⁻¹⁷ J
This work will be converted into the kinetic energy of charge .
Thus K.E = 1.02 x 10⁻¹⁷ J
<span>1.0344645 MJ
The minimum energy need is the potential energy of the car at the top of the ramp and is given by
mass*gravity*height
mass is known, gravity is assumed to be 9.81m/s^2 as it is on earth, and height must be calculated using trigonometry.
height=sin(9 degrees)*710m=111meters
so
potential energy = 950kg*111m*9.81m/s^2=1.0344645 MJ
Using the law of the conservation of energy we can assume that the energy expended to push the car up the incline was at least the potential energy gained by moving 111m against the pull of gravity.</span>
Answer: speed of light in solid = 1.88 * 10^8 m/s
Frequency is constant
Explanation: The relationship between the velocity of light wave and wavelength is given by the formulae below
V = fλ
During refraction, the frequency of light is constant, thus we have that
V = kλ which implies that velocity is proportional to wavelength.
Hence, we have that
v1/ λ1 = v2/ λ2
Where v1 = velocity of light in air = 3 * 10^8 m/s
v2 = velocity of sound in solid
λ1 = wavelength of light in air = 670nm
λ2 = wavelength of light in solid = 420nm
By making v2 subject of formulae, we have that
v2 = v1 * λ2/ λ1
v2 = 3 * 10^8 * 420nm/ 670nm
v2 = 3 * 10^8 * 0.6268
v2 = 1.88 * 10 ^8 m/s
b)
During refraction the frequency of light wave is constant this is because light consist of photons which has energy. it energy needs to be constant and for energy (E=hf) to be constant, frequency would be constant too.
