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liraira [26]
2 years ago
5

A quantity of HI was sealed in a tube, heated to 425°C and held at this temperature until

Chemistry
1 answer:
nordsb [41]2 years ago
8 0

The equilibrium concentration of H₂ : c. 9.55 x 10⁻³ M

<h3>Further explanation</h3>

Given

Kc = 54.6 at 425°C

The concentration of Hl = 0.0706 mol/L

Required

The equilibrium concentration of H₂ (and I₂)

Solution

\tt Kc=\dfrac{[HI]^2}{[H_2][I_2]}\\\\54.6=\dfrac{0.0706^2}{[H_2][I_2]}

[H₂][I₂]=[H₂]²

\tt [H_2][I_2]=\dfrac{0.0706^2}{54.6}=[H_2]=9.55\times 10^-3~M

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