Answer:
Explanation:
For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:
where
q is the magnitude of the charge
v is the velocity
B is the magnetic field strength
In this problem,
So the force experienced by the electrons is
Hello!
A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring?
0.57 m
0.64 m
0.80 m
1.25 m
Data:
For a spring (or an elastic), the elastic potential energy is calculated by the following expression:
Where k represents the elastic constant of the spring (or elastic) and x the deformation or displacement suffered by the spring.
Solving:
Answer:
The displacement of the spring = 0.8 m (or 0.80 m)
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I Hope this helps, greetings ... Dexteright02! =)