Answer:
Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.
Explanation:
Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.
We will assume that the only reactants are x and y and that the only product is xy.
Based on the law of mass conservation, mass is an isolated system that can neither be created nor destroyed.
Applying this concept to the chemical reaction, we will find that the total mass of the reactants must be equal to the total mass of the products,
therefore:
mass of x + mass of y = mass of xy
12.2 + mass of y = 78.9
mass of y = 78.9 - 12.2 = 66.7 grams
Explanation:
a. Adding a catalyst
no effect
.( Catalyst can only change the activation energy but not the free energy).
b. increasing [C] and [D]
Increase the free energy
.
c. Coupling with ATP hydrolysis
decrease the free energy value
.
d.Increasing [A] and [B]
decrease the free energy.
Answer is: A. Chemical energy to electromagnetic energy and thermal energy.
Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.
This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).
Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.
Answer:
Volume of lithium atom is found to be 1.47 X 10⁻²⁹ m³
Explanation:
Let us consider the volume of atom as a sphere (but it is little complex than that). This volume is mathematically expressed as,
----------------------------------------------------------------------------------------(Eq. 1)
Here, R is the radius of lithium atom. The radius is given in picometers, so firstly let us convert it into meters
placing this value in Eq.1 the required result is achieved
V= 1.47 X 10⁻²⁹ m³
