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Nutka1998 [239]
2 years ago
11

At low temperatures and high pressures ethene gas C2H4(g), does not behave like an ideal gas. Use chemical principles to explain

why this is?
Chemistry
1 answer:
Luba_88 [7]2 years ago
6 0

Answer:

The particles of an ideal gas have no volume and no attractions for each other.  In a real gas, however, the molecules do have a measurable volume. The molecules of real cases have intermolecular attractions for each other.

An ideal gas behaves like a real gas under the conditions of low temperature and high pressure.

This is because at low temperature and high pressure molecules of gas will have negligible kinetic energy and strong force of attraction.

Thus ethene gas does not behave like an ideal gas at low temperatures and high pressures.

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<span>100. ppb of chcl3 in drinking water means  100 g of CHCl3 in 1,000,0000,000 g of water

Molarity, M

M = number of moles of solute / volume of solution in liters

number of moles of solute = mass of CHCl3 / molar mass of CHCl3

molar mass of CHCl3 = 119.37 g/mol

number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol

using density of water = 1 g/ ml => 1,000,000,000 g = 1,000,000 liters

M = 0.838 / 1,000,000 = 8.38 * 10^ - 7 M <----- answer

Molality, m

m = number of moles of solute / kg of solvent

number of moles of solute = 0.838

kg of solvent = kg of water = 1,000,000 kg

m = 0.838 moles / 1,000,000 kg = 8.38 * 10^ - 7 m <----- answer

mole fraction of solute, X solute

X solute = number of moles of solute / number of moles of solution

number of moles of solute = 0.838

number of moles of solution = number of moles of solute + number of moles of solvent

number of moles of solvent = mass of water / molar mass of water = 1,000,000,000 g / 18.01528 g/mol = 55,508,435 moles

number of moles of solution = 0.838 moles + 55,508,435 moles = 55,508,436 moles

X solute = 0.838 / 55,508,435 = 1.51 * 10 ^ - 8 <------ answer

mass percent, %

% = (mass of solute / mass of solution) * 100 = (100g / 1,000,000,100 g) * 100 =

% = 10 ^ - 6 % <------- answer
</span>
7 0
2 years ago
Read 2 more answers
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Answer:

C

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0.5= N/6.02×10^23

N= 3.01×10^23

5 0
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The combustion of propane is best described as an
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<h3><u>Answer;</u></h3>

Exothermic chemical reaction

<h3><u>Explanation;</u></h3>
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5 0
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Ethyne (C2 H2 (g), mc032-1.jpgHf = 226.77 kJ/mol) undergoes complete combustion in the presence of oxygen to produce carbon diox
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answer: -1255.6 kJ/mo1
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2 years ago
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