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BabaBlast [244]
1 year ago
3

A bicycle camper rides from her starting point to her first campsite one day, then continues to a second campsite the next day.

If her average speed for the two days equals the average of her speeds each day, what must be true about her journey?
Physics
1 answer:
Korolek [52]1 year ago
6 0

Answer:

is there any more to this question

Explanation:

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Large and small numbers are often best entered in exponential notation. For example, the mass of the earth is 5.98x1024 kg and t
Doss [256]

Answer:

The charge to mass ratio is -1.76\times10^{11}

Explanation:

Mass\ of\ electron=m_e=9.11\times10^{-31} kg\\ Charge\ of\ the\ electron=q_e=-1.60\times10^{-19} C\\

We need to find how much charge is contained  in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:

\frac{Charge\ of\ electron}{Mass\ of\ electron}=\frac{q_e}{m_e}\frac{C}{kg}=\frac{-1.60\times10^{-19} C}{9.11\times10^{-31} kg}=-1.76\times10^{11} \frac{C}{kg}

4 0
2 years ago
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a glass vessel is completely filled with 340 gram of water at zero degree celsius what weight of Mercury will overflow when the
Svetlanka [38]

Answer:

A glass flask whose volume is 1000 cm ^3 at 0.0 ^oC is completely filled with mercury at this.  Every substance when heat energy is supplied, expands due to the  Rate of thermal expansion will be different for different materials. Volume of the glass flask and mercury at 0 degree Celsius V0=1000cm3=1×10−3m3 V 0

Explanation:

hope dis help!!!

6 0
2 years ago
An object of mass 24kg is accelerated up a frictionless place incline at an angle of 37° with horizontal by a constant force, st
RoseWind [281]

a) Average power: 1425 W

b) Instantaneous power at 3.0 sec: 2850 W

Explanation:

a)

The motion of the object along the ramp is a uniformly accelerated motion (because the force applied is constant), so we can use the suvat equation

s=ut+\frac{1}{2}at^2

where

s = 18 m is the displacement along the ramp

u = 0 is the initial velocity

t = 3.0 s is the time taken

a is the acceleration of the object along the ramp

Solving for a,

a=\frac{2s}{t^2}=\frac{2(18)}{(3.0)^2}=4 m/s^2

Now we can apply Newton's second law to find the net force on the object:

F=ma=(24 kg)(4 m/s^2)=96 N

This net force is the resultant of the applied force forward (F_a) and the component of the weight acting backward (mg sin \theta), so we can find what is the applied force:

F=F_a - mg sin \theta\\F_a = F+mg sin \theta = 96+(24)(9.8)(sin 37^{\circ})=237.5 N

where

m = 24 kg is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

Now we can finally find what is the work done by the applied force, which is parallel to the ramp, therefore:

W=F_a s = (237.6)(18)=4276 J

where s = 18 m is the displacement.

Therefore the average power needed is:

P=\frac{W}{t}=\frac{4276}{3}=1425 W

b)

The instantaneous power at any point of the motion is given by

P=F_av

where

F_a is the force applied

v is the velocity of the object

We already calculated the applied force:

F_a=237.5 N

While since this is a uniformly accelerated motion, we can find the velocity at the end of the 3.0 seconds using the suvat equation:

v=u+at=0+(4)(3.0)=12.0 m/s

And therefore, the instantaeous power at 3.0 sec is:

P=Fv=(237.5)(12)=2850 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

8 0
2 years ago
During a hurricane, the atmospheric pressure inside a house may blow off the roof because of the reduced pressure outside. If ai
m_a_m_a [10]

Answer:

817.5 Pa

Explanation:

From Bernoulli's equation, considering thst there is no height difference then

P1+½d(v1)²=P2+½d(v2)²

P1-P2=½d(v2²-v1²)

∆P=½d(v2²-v1²)

Where P represent pressure, d is density and v is velocity. Subscripts 1 and 2 represent inside and outside. ∆P is tge change in pressure

Given the speed at roof top as 128 km/h, we convert it to m/s as follows

128*1000/3600=35.555555555555=35.56 m/s

Velocity at the bottom of roof is 0 m/s

Density is given as 1.293 kg/m³

∆P=½*1.293*(35.56²-0)=817.5 Pa

5 0
2 years ago
⦁ A speed skater increases her speed form 10 m/s to 12.5 m/s over a period of 3 seconds while coming out of a curve of 20 m radi
Thepotemich [5.8K]

Answer:

7.85 m/s^2

Explanation:

linear or tangential acceleration= dv/dt

⇒a_t= \frac{12.5-10}{3}

=0.83 m/s^2

radial acceleration is given by = \frac{v^2}{r}

⇒a_r =\frac{12.5^2}{20}

= 7.81 m/s^2

total acceleration

a_T= \sqrt{a_t^2+a_r^2}

putting values we get

a_T= \sqrt{0.83^2+7.81^2}

= 7.85 m/s^2

3 0
2 years ago
Read 2 more answers
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